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On continuous and locally one-to-one map |
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| Jan31-13, 10:00 AM | #1 |
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On continuous and locally one-to-one map
Whether a continuous and locally one-to-one map must be a (globally) one-to-one map? If the answer is not. Might you please give a counter-example? Thank in advance.
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| Jan31-13, 10:35 AM | #2 |
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The answer is no. Consider the mapping [itex]\mathbb{R} \rightarrow S^1[/itex] defined by [itex]x \mapsto \exp(2\pi i x)[/itex].
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| Jan31-13, 11:03 AM | #3 |
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Got it, many thanks!
Another question: whether a continuous and locally one-to-one map between two open spaces, e.g., two connected open set of R^n, must be a (globally) one-to-one map? |
| Jan31-13, 11:53 AM | #4 |
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On continuous and locally one-to-one map[tex]\mathbb{C}\setminus \{0\}\rightarrow \mathbb{C}:z\rightarrow z^2[/tex] |
| Jan31-13, 12:11 PM | #5 |
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Thanks a lot!
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