How Long Would It Take San Chai to Catch Dao Ming Xi in Meteor Garden?

[imusthave]

Meteor Garden Problem :(

Homework Statement

Hi Guys.. I am really having a trouble in physics.. :( I really can' t solve uniform accelerated motion problems correctly. Can someone help me? please.. Our teacher gave this Meteor Problem. Help Please.

An unforgettable scene from “Meteor Garden”
San Chai was holding a bag of lemons when she saw Dao Ming Xi in a bus moving at a constant velocity of 1.5 m/s. She stood still mixed in an array of emotions. Then, as the bus was about 15 m away, she ran to catch up, accelerating at a rate of 0.40m/s2. If she continued to running and did not trip over, how long would it have took her to catch up?

Homework Equations

the four kinematic equation

The Attempt at a Solution

idk

 

[Cyosis]

Forum rules state that you have to provide an attempt at a solution or at the very least try to describe exactly where the problem lies and why you can't continue from there. You haven't even put the effort into listing the equations.

You will need two equations one for the bus and one for San Chai. Which two equations do you think you will need and why? Write them out in formula form and explain the variables to me.

Answering with 'idk' is not allowed!

 

[tomcue]

Dear student,

I understand that you are having trouble with uniform accelerated motion problems in your physics class. I can assure you that this is a common struggle for many students and it is completely normal to ask for help when you are having trouble understanding a concept.

In order to solve this Meteor Garden problem, you will need to use the four kinematic equations. These equations relate the variables of displacement, velocity, acceleration, and time. It is important to first identify which equation to use based on the given information.

In this case, we know that San Chai is accelerating at a rate of 0.40m/s2 and we are looking for the time it takes for her to catch up to Dao Ming Xi. The equation that relates these variables is t = vf - vi/a, where t is time, vf is final velocity, vi is initial velocity, and a is acceleration.

To solve for time, we need to first find the final velocity of San Chai. We can do this by using the equation vf = vi + at, where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is time. We know that San Chai's initial velocity is 0 m/s since she was standing still, and her acceleration is 0.40m/s2. Plugging these values into the equation, we get vf = 0 + (0.40m/s2)(t), which simplifies to vf = 0.40t.

Now, we can plug this value for final velocity into the first equation, t = vf - vi/a. This gives us t = (0.40t - 1.5)/0.40. We can then solve for t by isolating it on one side of the equation. This gives us t = 1.5/0.40 = 3.75 seconds.

Therefore, it would have taken San Chai 3.75 seconds to catch up to Dao Ming Xi if she continued to run without tripping over.

I hope this helps you understand how to approach and solve uniform accelerated motion problems. Remember, practice makes perfect, so don't be discouraged if it takes some time to grasp the concept. Keep asking for help and keep practicing, and you will surely improve.

Best of luck with your studies.

Sincerely,
A scientist