Monique said:If x+2y=2 and (x+y)2=9, what is the value of y?
And the answer is not -1.. what is the trick here that I'm missing? The answer is supposed to be 5.
The value of y is 1.
To solve for y, we can substitute the given value of x in the first equation into the second equation, giving us (1+y)^2=9. We can then solve for y by taking the square root of both sides and simplifying.
First, we substitute the given value of x in the first equation into the second equation, giving us (1+y)^2=9. Next, we expand the equation to get 1+2y+y^2=9. Then, we move all the terms to one side to get y^2+2y-8=0. Using the quadratic formula, we can solve for y, giving us y=1 or y=-4. However, since the original equation states that x+2y=2, we can only have a positive value for y, so the value of y is 1.
Yes, there are two possible solutions for y, which are y=1 and y=-4. However, since the original equation states that x+2y=2, we can only have a positive value for y, so the value of y is 1.
Yes, we can also use substitution to solve for y. We can rearrange the first equation to get x=2-2y, and then substitute this into the second equation, giving us (2-2y+y)^2=9. We can then solve for y using this equation, giving us the same solution of y=1.