Minimum Angular Speed for Safe Ride on ROTOR

In summary, the ROTOR is an amusement park ride where people stand against the inside of a cylinder. The floor drops out once the cylinder is spinning fast enough. To find the minimum angular speed so that people don't fall out, you need to consider the forces acting on the person and set up an appropriate equation. The normal force exerted by the spinning cylinder wall and the coefficient of friction must be taken into account. The weight of the person can be represented as mg, with m eventually cancelling out in the equation.
  • #1
evan4888
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The ROTOR is an amusement park ride where people stand against the inside of a cylinder. Once the cylinder is spinning fast enough, the floor drops out. If the coefficient of friction is 0.42 and the cylinder has a radius of 2.5m, what is the minimum angular speed of the cylinder so that the people don't fall out?

How would I go about solving this? I don't even know where to start!
 
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  • #2
let m = mass of a person
let n = normal force exerted on the person by the (spinning) cylinder wall
let μ = the coefficient of friction
let g = acceleration of gravity

Start by thinking about the forces acting on the person along the vertical axis (up and down) in terms of the above. What has to be true if the person doesn't fall? Set up the appropriate equation to express this.

Then, think about what produces the normal force and you should be able to find your answer.
 
  • #3
I think I know how to find the max cetripetal acceleration with ac = v2/r or
v = sq. root of r(ac). But without knowing the weight of the people inside the ride, I just don't understand how you would find the minimum angular speed.
 
  • #4
It's the speed that gives you the n that you need.

You do know the weight: mg. The m will eventually cancel out.
 

What is minimum angular speed?

Minimum angular speed, also known as critical angular speed, is the lowest rotational velocity at which an object can maintain its shape and stability. It is a crucial parameter in the study of rotational motion in physics.

How is minimum angular speed calculated?

The formula for calculating minimum angular speed is ω = √(g/r), where ω is the angular speed, g is the gravitational acceleration, and r is the radius of the rotating object. This formula is derived from the equation for centripetal acceleration (a = ω²r) and the condition for circular motion (a = g).

What happens if an object rotates at a speed lower than the minimum angular speed?

If an object rotates at a speed lower than the minimum angular speed, it will not have enough centripetal force to counteract the centrifugal force, causing it to lose its shape and stability. This is known as "flying apart" or "flying off."

How does minimum angular speed affect the stability of rotating objects?

Minimum angular speed is directly proportional to the stability of rotating objects. The higher the minimum angular speed, the more stable the object will be. This is because a higher speed means a greater centripetal force, which can counteract the centrifugal force and maintain the object's shape.

Can minimum angular speed be altered?

Yes, minimum angular speed can be altered by changing the radius of rotation or the angular velocity. A smaller radius or higher angular velocity will result in a higher minimum angular speed, while a larger radius or lower angular velocity will result in a lower minimum angular speed.

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