Calculating Force: Understanding the 1.5m Distance in Baseball Pitching Protest

  • Thread starter Hitokiri
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In summary, the conversation discusses the calculation of the force exerted by a baseball pitcher on a ball, thrown straight up in protest against an umpire's call. The pitcher moves his hand through a distance of 1.5 m, and the force is found using the formula W = F*d. The discussion also mentions the relation between speed, force, and the distance over which the force is applied.
  • #1
Hitokiri
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Ok, i just need to verify what this question means:

A baseball pitcher throws a ball straight up into the air at a speed of 20 m/s as a protest against the umpire's calls. In the process, he moves his hand through a distance of 1.5 m. If the ball has a mass of 0.15 kg, find the force he exerts on the ball to give it this upward speed. Note that the force of gravity is acting against the motion of the ball.


Ok, so i just have a question on what the significance of the "1.5 m " distance.
 
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  • #2
HINT: Work = Force X distance
 
  • #3
I see what is going on... W= Ek so, F*s = ((m*v*v)/2) . The speed is related to the Force and the distance the force was applied over.

I new that F= m*a. so speed is related to force over time. I never really considered the distance that a force is applied over.

If Hitokiri is still visiting this forum It would be interesting to know if Tides hint was of help.
 

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