- #1
suspenc3
- 402
- 0
Ok, I think I've figured this out but the book gives me different answer for my x value:
[tex]y=4-x^2[/tex] [tex]y=0[/tex]
[tex]A= \int_0^2(4-x^2)dx[/tex] A=16/3
[tex]x bar= \frac{3}{16}\int_0^2 x(4-x^2)dx[/tex]
and this comes out to 3/4..The book says 0 for the X-value...where did I go wrong?
[tex]y=4-x^2[/tex] [tex]y=0[/tex]
[tex]A= \int_0^2(4-x^2)dx[/tex] A=16/3
[tex]x bar= \frac{3}{16}\int_0^2 x(4-x^2)dx[/tex]
and this comes out to 3/4..The book says 0 for the X-value...where did I go wrong?