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unscientific
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F=ma a = F/m Light's mass: 0 N = infinite acceleration?
Why is this on the relativity board? And if 0 N means "0 Newtons", ie F=0, this will mean a=0 for a finite mass, not a=infinity.unscientific said:F=ma a = F/m Light's mass: 0 N = infinite acceleration?
F=ma is Newtonian classical physics. Cannot apply to relativistic concepts.unscientific said:F=ma a = F/m Light's mass: 0 N = infinite acceleration?
light has zero rest mass!unscientific said:light has 0 mass, and I am talking about light being 0 mass here, jessem
But F=ma doesn't apply in relativity, although on this thread masudr mentioned that there is a similar equation relating the force 4-vector to the momentum 4-vector, [tex]f_{\mu} = \frac{d}{d\tau}p_{\mu}[/tex]. Also, you said "0 N", I assumed the N was short for "Newtons", which is a unit of force, not mass.unscientific said:light has 0 mass, and I am talking about light being 0 mass here, jessem
It is true in a sense in calculus, though--the limit of 1/N as N approaches zero is infinity.actionintegral said:This isn't even a physics question! Every sixth grader tries to divide by zero thinking the answer is infinity. This belongs in the homework section.
The concept refers to the idea that light does not have any mass and therefore can travel at the speed of light, which is considered to be infinite acceleration.
Light's mass cannot be measured directly as it does not have any mass. However, its energy can be measured using the equation E=mc^2, where c is the speed of light. This shows that light has energy, but not mass.
No, according to the current understanding of physics, light does not have any form of mass. It is considered to be a massless particle.
Light's lack of mass allows it to travel at the speed of light and have infinite acceleration. It also means that it does not experience the effects of gravity and can only be affected by it through its energy and momentum.
This concept is important as it helps us understand and explain the behavior of light, which plays a crucial role in many aspects of physics, such as optics, electromagnetism, and quantum mechanics. It also helps us understand the fundamental principles of the universe and the nature of matter and energy.