- #1
kasse
- 384
- 1
Task:
Find a potential function for the conservative vector field (y,x,1)
My work:
(Df/Dx, Df/Dy and Df/Dz are the partial derivatives)
Df/Dx=1, Df/Dy=x, Df/Dz=1
I take the first eq. and integrate, so that I get
f(x,y,z) = yx + C
I then derivate with respect to y:
Df/Dy= x + C '
I compare this to the other eq. Df/Dy=x, hence C ' is 0, and consequently C is also 0.
My answer is then
f(x,y,z)=yx
Which is wrong! Correct answer is yx+z. Where do I fail?
Find a potential function for the conservative vector field (y,x,1)
My work:
(Df/Dx, Df/Dy and Df/Dz are the partial derivatives)
Df/Dx=1, Df/Dy=x, Df/Dz=1
I take the first eq. and integrate, so that I get
f(x,y,z) = yx + C
I then derivate with respect to y:
Df/Dy= x + C '
I compare this to the other eq. Df/Dy=x, hence C ' is 0, and consequently C is also 0.
My answer is then
f(x,y,z)=yx
Which is wrong! Correct answer is yx+z. Where do I fail?