- #1
salman213
- 302
- 1
1. Find the SMALLEST angle between the vectors T and S
Given vectors T = 2ax — 6ay + 3az and S =ax + 2ay + az,
See the thing I am confused about is whether to use Cross Product or Dot Product. I used the dot product formula
TdotS = |T||S|cos
and solved for cos theta ((theta = cos-1))
I got 114 degrees
The solution I have uses CROSS PRODUCT and finds an angle 65 Degrees
I don't get why the cross product would give a smaller angle? Can anyone tell me
If i take 114 - 180 i get -66 but I don't get why I would subtract 180 *and also its a negative angle then..HELP!
Given vectors T = 2ax — 6ay + 3az and S =ax + 2ay + az,
See the thing I am confused about is whether to use Cross Product or Dot Product. I used the dot product formula
TdotS = |T||S|cos
and solved for cos theta ((theta = cos-1))
I got 114 degrees
The solution I have uses CROSS PRODUCT and finds an angle 65 Degrees
I don't get why the cross product would give a smaller angle? Can anyone tell me
If i take 114 - 180 i get -66 but I don't get why I would subtract 180 *and also its a negative angle then..HELP!
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