- #1
Quezar
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A soccer ball is kicked with an initial speed of 5.9 m/s in a direction 24.0° above the horizontal. Find the magnitude and direction of its velocity at the following times. (Take the +x axis to be parallel to the ground, in the direction that the ball is kicked.)
(a) 0.250 s after being kicked
1 ___ m/s
2 ___ degrees (counterclockwise from the +x axis)
(b) 0.500 s after being kicked
1 ___ m/s
2 ___ degrees (counterclockwise from the +x axis)
vx = v0x +ax * t
vy= v0y + ay * t
cos24=x/5.9
1/2*-9.8*.25^2+2.4*.25 = .29
vx = 5.4 vy = .29
thats all I could figure out
(a) 0.250 s after being kicked
1 ___ m/s
2 ___ degrees (counterclockwise from the +x axis)
(b) 0.500 s after being kicked
1 ___ m/s
2 ___ degrees (counterclockwise from the +x axis)
vx = v0x +ax * t
vy= v0y + ay * t
cos24=x/5.9
1/2*-9.8*.25^2+2.4*.25 = .29
vx = 5.4 vy = .29
thats all I could figure out