- #1
Abuattallah
- 4
- 0
Hello,
I am a grad student preparing for a quals. I am using H. and Kunze book.
the problem is:
let V be a n-dim vector space over F. and let [itex]B[/itex]={[itex]a_1,a_2,..., a_n[/itex]} be an ordered bases for V.
a- According to them 1, there is a unique Linear operator T on V such that
[itex]Ta_i=a_{(i+1)}[/itex] , i=1,...,n. and [itex]Ta_n=0[/itex].
what is the matrix [itex]A[/itex] of [itex]T[/itex] in the ordered bases B.
b- prove that [itex]T^n=0, and\ \ \ T^{n-1}≠ 0[/itex].
c- Let S be any linear operator on V such that [itex]S^n=0\ \ \ but\ \ \ S^{n-1}≠0[/itex]. Prove that there is an ordered bases [itex]B'[/itex] such that the matrix of [itex]S[/itex] in the bases [itex]B'[/itex] is the matrix [itex]A[/itex] of part (a).
Solution Attempt.
Obviously we have for (a)[itex]A= \begin{bmatrix}
0 & 0&... & 0 &0\\
1 & 0 & 0&...&0 \\
0&1&0&...&0\\
.\\
.\\
0&0&...&1&0
\end{bmatrix}[/itex]
for (b) its obvious.
my problem is with the last question. I tried to justfy it by two ways, the first one is to find an ivertible linear transformation [itex]U:V→V[/itex] such that [itex]S=UTU^{-1}[/itex], then we will be done and such a bases exists. The second way is that I am trying to show the follwing:
there exist at least on vector in the bases [itex]B[/itex] such that [itex]S^ia_i≠0[/itex] for [itex]i=1,..,n-1.[/itex] and I am considering the set [itex]B'=[/itex]{[itex]a_i, Sa_i,S^2a_i,...,S^{n-1}a_i[/itex]}. Note if we proved [itex]B'[/itex] is a bases, then [itex]_{B'}=A[/itex].i.e. the matrix of [itex]S[/itex] relative to the bases [itex]B'[/itex] is A.
Unfotunatly, I could not get to an end with both ways.
Am I doing the right thing? Any suggestions?.
Thank you in Advance.
I am a grad student preparing for a quals. I am using H. and Kunze book.
the problem is:
let V be a n-dim vector space over F. and let [itex]B[/itex]={[itex]a_1,a_2,..., a_n[/itex]} be an ordered bases for V.
a- According to them 1, there is a unique Linear operator T on V such that
[itex]Ta_i=a_{(i+1)}[/itex] , i=1,...,n. and [itex]Ta_n=0[/itex].
what is the matrix [itex]A[/itex] of [itex]T[/itex] in the ordered bases B.
b- prove that [itex]T^n=0, and\ \ \ T^{n-1}≠ 0[/itex].
c- Let S be any linear operator on V such that [itex]S^n=0\ \ \ but\ \ \ S^{n-1}≠0[/itex]. Prove that there is an ordered bases [itex]B'[/itex] such that the matrix of [itex]S[/itex] in the bases [itex]B'[/itex] is the matrix [itex]A[/itex] of part (a).
Solution Attempt.
Obviously we have for (a)[itex]A= \begin{bmatrix}
0 & 0&... & 0 &0\\
1 & 0 & 0&...&0 \\
0&1&0&...&0\\
.\\
.\\
0&0&...&1&0
\end{bmatrix}[/itex]
for (b) its obvious.
my problem is with the last question. I tried to justfy it by two ways, the first one is to find an ivertible linear transformation [itex]U:V→V[/itex] such that [itex]S=UTU^{-1}[/itex], then we will be done and such a bases exists. The second way is that I am trying to show the follwing:
there exist at least on vector in the bases [itex]B[/itex] such that [itex]S^ia_i≠0[/itex] for [itex]i=1,..,n-1.[/itex] and I am considering the set [itex]B'=[/itex]{[itex]a_i, Sa_i,S^2a_i,...,S^{n-1}a_i[/itex]}. Note if we proved [itex]B'[/itex] is a bases, then [itex]
Unfotunatly, I could not get to an end with both ways.
Am I doing the right thing? Any suggestions?.
Thank you in Advance.
Last edited: