Why is the Speed of Light Squared in Special Relativity?

In summary, the conversation discusses the concept of squaring the speed of light, with some individuals questioning the logic behind it. However, it is explained that squaring a constant velocity is necessary in certain equations, such as calculating energy. The conversation also touches on the idea that the speed of light is constant for all observers, regardless of their state of motion.
  • #1
Swampeast Mike
48
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Special relativity says that the speed of light is a constant regardless of the speed of the observer.

I've always been troubled with the idea of squaring that speed (C ^ 2) unless speed of light to the zero power (C ^ 0) also has meaning at the same time and in the same space; the net effect to an observer fixed in time being 1 = 1 where 0 = 0.

To an observer fixed in space, 0 would appear equal to 1 at the same time that 1 appeared equal to 0.

To a real observer, part of one appears to be in zero and part of zero appears to be in one.

Please destroy this view of special relativity.
 
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  • #2
What's wrong with squaring a number? If this is an assault on SR you might want to post this in the theory development section.
 
  • #3
The speed of light squared is not a velocity. It appears in some expressions where velocity^2 appears, like E=mc^2 (compare to E=(1/2)mv^2).

The speed of light is constant for all observers regardless of their state of motion, this is however totally unrelated to the properties of c^2.
 
  • #4
Nothing wrong with squaring a number.

What I have a problem understanding is squaring a constant that cannot change for an observer who is fixed in both time and space.
 
  • #5
The speed of light squared is not a velocity

My exact problem. Speed of light squared is a concept that depends on your time/space perspective.
 
  • #6
Swampeast Mike said:
What I have a problem understanding is squaring a constant that cannot change for an observer who is fixed in both time and space.
Why would you have a problem squaring a constant? (I have no idea what you mean by an observer "fixed in both time and space". The speed of light is an invariant: it has the same value as measured by anyone regardless of their motion.)

Do you have a problem with the formula for (non-relativistic) kinetic energy: [itex]{KE} = 1/2 m v^2[/itex] ? In that formula speed is not a constant, but is frame dependent. I trust that you are fine with that. So, if anything, squaring c should be even less of an issue.

Swampeast Mike said:
My exact problem. Speed of light squared is a concept that depends on your time/space perspective.
Actually, the speed of light, being frame independent, is less dependent on "time/space perspective" than ordinary, sub-light speeds. (But, even if something is frame-dependent, what prevents you from squaring it?)
 
  • #7
Maybe a calculus class may help. I don't fully understand the logic in squaring c either :pondering:
 
  • #8
Whenever you find a [itex]c^2[/itex] there's probably a way to write it differently, making the source of the square more obvious.
Look e.g. at [itex]E=mc^2[/itex] which is usually written more correctly as [itex]E/c=\sqrt{(m_0c)^2+p^2}[/itex]. The [itex]c[/itex] on the left part is a scaling factor while the [itex]c[/itex] in the right part is a velocity.
In [itex] t'=\gamma(t-vx/c^2)=\gamma(t-(v/c)(x/c))[/itex], [itex]v/c[/itex] is a ratio of velocities while in [itex]x/c[/itex] the [itex]c[/itex] is a correction in the scale of [itex]x[/itex].
Try it. You'll find for most cases either this separation in a velocity and a scaling factor, while in other cases you may find the square to have its roots in a Minkowski equivalent of a "Pythagorean" operation ([itex]A^2=C^2-B^2[/itex] for Minkowski space, equivalent to [itex]C^2=A^2+B^2[/itex] for Euclidean space).
 
  • #9
Do you have a problem with square rooting pi? [tex]r=\frac{\sqrt{A}}{\sqrt{\pi}}[/tex] This is simply a rearranged version of [tex]A={\pi}r^2[/tex], which can be used to find the radius of a circle if you know the area.


What about [tex]\sqrt{E}=\sqrt{m}c[/tex]? You don't have to square c; [tex]E=mc^2[/tex] is just a little more elegant than the former.
 
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  • #10
eNathan said:
Maybe a calculus class may help. I don't fully understand the logic in squaring c either :pondering:
Its exctly the same as squaring velocity in the kinetic energy equation - that's what you have to do to turn a velocity into an energy (well, that and multiply by mass and a proportionality constant).

Bernoulli's equation also uses velocity squared -- to calculate pressure. So it isn't an unusual thing to square a velocity..
Swampeast Mike said:
Nothing wrong with squaring a number.

What I have a problem understanding is squaring a constant that cannot change for an observer who is fixed in both time and space.
The speed of light is a constant, but it is also a real, physical speed.

Lets look at it from the other angle: why would it be a problem to square a constant (others have provided examples...)?
 
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  • #11
c is not a "number" in the standard MKS unit system, it is a velocity. Squaring a velocity makes sense in certain cirumstances, as when one squares the velocity and multiplies by the mass to calculate the energy. The units work out correctly

energy - force * distance = mass * acceleration * distance = kg * (m/s^2) * m =
kg * (m/s)^2

Thus we see that unitwise, energy is naturally the product of a mass multipled by the square of a velocity.

Squaring a constant velocity makes sense under the same circumstances that squaring a non-constant velocity makes sense. The fact that the velocity is constant is really irrelevant to the units.
 
  • #12
Let's see. How about h**0 = c **0= 1 = e**0, etc, where h is Planck's constant, and e is the electron's charge. I'm 6'2 tall. As long as observers are moving perpendicular to me, I will be 6'2 for all those observers. If my height is H, then all those observers will see the same value for H**1/7.

The usual rules of algebra proclaim that the values of c**N, with N any real number from - infinity to + infinity are the same for all inertial observers. Hint: the rules of algebra are Lorentz invariant.

Regards,
Reilly Atkinson
 
  • #13
No Problem Squaring pi

Speed of light involves time; pi involves space.

We comprehend time as a non-zero because nothing can move at that speed.

Yet something appears to change between objects separated by space.

To both the similarity and change between objects, time is zero.
 
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  • #14
Swampeast Mike said:
Speed of light involves time; pi involves space.

We comprehend time as a non-zero because nothing can move at that speed.

Yet something appears to change between objects separated by space.

To both the similarity and change between objects, time is zero.

This makes no sense what-so-ever.

You have a problem with squaring properties that involve time? What about acceleration which is distance/time²?
 
  • #15
I suppose we'd better not square Planck's constant, either.

The Bohr radius

http://musr.physics.ubc.ca/~jess/hr/skept/QM1D/node3.html

however does involve the square of Planck's constant. Since h-bar has units of

kg m^2 / sec

I suppose this must be a bad thing since it's even more complicated in its units than a velocity, and it's a universal constant, to boot.

(Personally, I still don't see the problem).

There are numerous other places in physics where fundamental constants are squared. I would just try and tell Swampbeast to "deal with it"
 
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  • #16
I believe that the OP has an issue with the invariant C being expressed, mathematically, beyond the constants' immutable value.
In a sense the OP is correct is such concern, as a constant value can not be un-reasonably altered in any equation.
 
  • #17
pallidin said:
I believe that the OP has an issue with the invariant C being expressed, mathematically, beyond the constants' immutable value.

Nowhere in any equation of special relativity is 'c' anything other than 'c'. Squaring the speed of light doesn't give you a new value of 'c', it gives you a value of 'c2'

In a sense the OP is correct is such concern, as a constant value can not be un-reasonably altered in any equation.

There is nothing correct about the OP.

(edit: except the first line, that is)
 
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  • #18
Tom Mattson said:
Nowhere in any equation of special relativity is 'c' anything other than 'c'. Squaring the speed of light doesn't give you a new value of 'c', it gives you a value of 'c2

QUOTE]


You are incorrect: the squaring of "c" supposes a mathematical and practical scenario which is not possible, thus it becomes invalid by default.
Doing otherwise would be much like saying 1 squared is greater than 1.
They are both immutable constants.
 
  • #19
pallidin said:
You are incorrect: the squaring of "c" supposes a mathematical and practical scenario which is not possible, thus it becomes invalid by default.

No I'm not, and no it doesn't. Squaring the speed of light is not in any way contrary to the speed of light postulate. I have no idea of why anyone would think that it is.

Doing otherwise would be much like saying 1 squared is greater than 1.
They are both immutable constants.

This makes absolutely no sense.
 
  • #20
Are you then suggesting that c-squared is a valid condition? If so, it's inclusion in mathematics is valid.
What evidence, then, does anyone have for a c-squared phenomenon?
 
  • #21
pallidin said:
Are you then suggesting that c-squared is a valid condition?

I don't even know what you mean by c-squared as a condition. If you are asking me if the equations of relativity that contain c2 are validly derived from the postulates, and match experimental predictions, then I say "Yes, of course they are."

If so, it's inclusion in mathematics is valid.

This is ridiculous. Since when does any statement of any physical theory have any bearing on what is included in or excluded from mathematics?

What evidence, then, does anyone have for a c-squared phenomenon?

What is a "c-squared phenomenon"?
 
  • #22
Tom Mattson said:
I don't even know what you mean by c-squared as a condition. If you are asking me if the equations of relativity that contain c2 are validly derived from the postulates, and match experimental predictions, then I say "Yes, of course they are."



This is ridiculous. Since when does any statement of any physical theory have any bearing on what is included in or excluded from mathematics?



What is a "c-squared phenomenon"?

Tom, I want to thank you for granting lattitude towards someone(myself) who is not well versed in mathematics. It is my hope that I can learn from such discourse.

In answer to your question "What is a c-squared phenomenon"?:
My position, in light of your statement "Since when does any statement of any physical theory have any bearing on what is included in or excluded from mathematics?" holds my position somewhat mute.

Thanks again for your instruction.
 
  • #23
Glad You Mentioned Planck's Constant

It leads directly to the duality of energy transfer between separated bodies. After all, he saw it as nothing more than a mathematical convenience.

Particle and/or wave, both and/or neither at the same time.

Go back to the original post. [My apologies for trying to express something that can only be described as nothing in simple words.]

My problem wasn't understanding the "speed of light squared" it was understanding how such works as an individual concept relative to both time and space.

If light can be both a something and a nothing, cannot its' speed be only measurable as a product? a sum? a difference? all? some?

Energy, radiation, light or whatever you want to call it always occurs BOTH WAYS between separated bodies yet we tend to conviently overlook the view of the other observer.
 
  • #24
Dear Mike : There is no physics in this post, or in the OP. Hence, there can be no physical discussion about it. If you can address the problem in terms of well-defined physical constructs, do so, and a physical discussion may result.

Else, this thread will have to be closed.
 
  • #25
At the risk of reviving a dead horse (have you tried giving mouth-to-mouth to one?), I would like to point out an almost DEFINITIVE treatment on this particular question:

J.J. Prentis Am. J. Phys. v.73, p.701 (2005).

He describes the derivation and the conceptual foundation behind mv^2/2 in painful detail. Anyone trying to make up their own ideas about this is required to first read this paper and understand it inside-out.

Zz.
 
  • #26
Swampeast Mike said:
I've always been troubled with the idea of squaring that speed (C ^ 2) unless speed of light to the zero power (C ^ 0) also has meaning at the same time and in the same space; the net effect to an observer fixed in time being 1 = 1 where 0 = 0.

I have no idea why this would trouble you, however, it does turn out that there is a branch of mathematics / physics that does something sort of similar to this. In D. Hestenes' "Geometric Algebra", the dot product and the cross product are combined into a single "multi-vector" operation. Hundreds of physicists and mathematicians use his theory. Hestenes' website is here:
http://modelingnts.la.asu.edu/

Geometric algebra is a subdivision of Clifford algebra. Where the standard physics education meets Clifford algebra is in the Pauli or Dirac gamma matrices, which are examples of geometric algebras defined on the manifold of 3-space and 4-dimensional space-time, respectively.

The reason I'm bringing this up is because the Geometric algebra crosses the usual boundaries of scalars, vectors and tensors. In the GA, for example, one can add a vector to a scalar and get what is called a "multivector". The laws of E&M, for example, can be written with very few symbols in this manner.

I disagree with the poster who said that "c" is a velocity. I believe instead that it is a speed. A velocity has a direction, "c" does not. But if you think of "c" as a velocity, then the conversion that takes you from c to c squared is a dot product.

The other half of a dot product, in Geometric algebra, is a cross product. In standard physics, a cross product takes two vectors and turns them into a "psuedovector". Undergraduates used to be taught that the result of a cross product is a "vector", but in grad school they get taught differently.

Now the operation of squaring a vector and getting back a scalar takes anobject of dimension 1 and turns it into an object of dimension 0. This is mighty odd stuff. To put it back into Dirac gamma matrix form, this gets back to the fact that the square of a gamma matrix is unity.

In the context of the gamma matrices, "unity" really means a 4x4 matrix with ones down the diagonal. That makes sense to me. But Clifford / geometric algebra is written without reference to matrices, and to me the implications of scaling laws with them is odd in the same way that the Swampeast Mike's comment is odd. Two things I do not understand that seem to be for the same reason.

Carl
 
  • #27
Carl is of course right with his speed-versus-velocity remark. I made the same error in one of my posts (as a bad excuse I could say that in Dutch the distinction doesn't exist :blushing: ).
Mortimer said:
Look e.g. at [itex]E=mc^2[/itex] which is usually written more correctly as [itex]E/c=\sqrt{(m_0c)^2+p^2}[/itex]. The [itex]c[/itex] on the left part is a scaling factor while the [itex]c[/itex] in the right part is a velocity. (Here it is a velocity if you ask me)
In [itex] t'=\gamma(t-vx/c^2)=\gamma(t-(v/c)(x/c))[/itex], [itex]v/c[/itex] is a ratio of velocities (here it is a speed) while in [itex]x/c[/itex] the [itex]c[/itex] is a correction in the scale of [itex]x[/itex].
Try it. You'll find for most cases either this separation in a velocity and a scaling factor, while in other cases you may find the square to have its roots in a Minkowski equivalent of a "Pythagorean" operation ([itex]A^2=C^2-B^2[/itex] for Minkowski space, equivalent to [itex]C^2=A^2+B^2[/itex] for Euclidean space).
The point I was trying to make still stands, by the way. If anyone can give examples that do not fit the criteria I described, I would be interested.
 
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  • #28
Dear Mike : There is no physics in this post, or in the OP.

I disagree. This is the most fundamental of physical questions when space and time are relative.

The speed of light (C) is also the speed of perfect conduction.
 
  • #29
Would you prefer [tex]E = \frac{m}{\epsilon_0 \mu_0}[/tex] instead?
 
  • #30
I like the idea of a scaling factor: E/c = mc, energy divided by c is equivalent to mass multiplied by c.

But perhaps Swampeast Mike, in his original post, mistakenly assumed that the energy was only released when the mass was actually moving at c-squared? That would perhaps explain his confusion...
 
  • #31
Swampeast Mike said:
My problem wasn't understanding the "speed of light squared" it was understanding how such works as an individual concept relative to both time and space.

If light can be both a something and a nothing, cannot its' speed be only measurable as a product? a sum? a difference? all? some?

Energy, radiation, light or whatever you want to call it always occurs BOTH WAYS between separated bodies yet we tend to conviently overlook the view of the other observer.

This completely mystifies me! Who said that "light can be both a something and a nothing? In what sense can light be "a nothing"?
Products, sum, differences, etc. are mathematical calculations. They have nothing to do with measuring the speed of light.
Finally, "energy, radiation, light or whatever you want to call it" doesn't "occur", it MOVES from one body to another- while I'm sure light COULD go both ways that is certainly not necessary. Do you have any evidence for this assertion?
 
  • #32
HallsofIvy said:
This completely mystifies me! Who said that "light can be both a something and a nothing? In what sense can light be "a nothing"?
Products, sum, differences, etc. are mathematical calculations. They have nothing to do with measuring the speed of light.
Finally, "energy, radiation, light or whatever you want to call it" doesn't "occur", it MOVES from one body to another- while I'm sure light COULD go both ways that is certainly not necessary. Do you have any evidence for this assertion?

Is light not a photon? Is a photon not both a something and a nothing? Or at least has the characteristics of both while being undefinable as either?

Light is a "nothing" in the sense that only nothing can travel at its' speed.

There are many forms of photons--light just happens to be the one that our eyes see. There are infrared photons, radio photons, ultraviolet photons, x-ray photons.

While energy in the form of light might not necessarily move both ways between bodies, energy in some form must. Evidence: energy in the form of heat transferring between bodies--you MUST subtract the energy moving from the cooler to the warmer object.
 
  • #33
Swampeast Mike said:
Is light not a photon? Is a photon not both a something and a nothing? Or at least has the characteristics of both while being undefinable as either?
Perhaps you are thinking of the fact that light (and everything) has characteristics of both particles and waves, but both particles and waves are something.

Swampeast Mike said:
Light is a "nothing" in the sense that only nothing can travel at its' speed.
Light doesn't have mass, but that still doesn't mean it's nothing. If it was nothing there would be no reason to say it travels and we wouldn't be talking about it. It doesn't exhibit any characteristics of "a nothing" because a nothing doesn't have characteristics to exhibit.
 
  • #34
There is an irony here, Mike - it seems to me that you are trying to argue against some philosophical aspect of light, but its you who is injecting that philosophical aspect by saying things that are factually wrong about the nature of light! Bizarre. Anyway, if you stopped looking for philosophical contradictions for a little while and learned what is actually known about the nature of light, I think these issues you are having would drop away.

Maybe that's overly optomistic though: to say that light is "nothing" is inexplicably bad science and philosophy. I can't fathom why you would suggest such a thing.
 
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  • #35
Really not trying to ask philosophic questions and I apologize if my vocabulary or nomenclature is failing me. If I am offering utter falsehoods, please let me know as that is not my desire.

Rather hard for me to consider a massless bundle of energy as being an object (or thing) in conventional terms. While you can certainly tell that I'm not a trained physicist, I have been studying deeply and intently for years before posing these questions.

Unless there has been some recent breakthrough of which I am unaware, there are still MANY unanswered questions about the nature of energy transfer between objects.

Am working on a book regarding hydronic (hot water) space heating for structures and much of it is devoted to the proportional delivery and production of heat. As I research and experiment, I find myself getting deeper and deeper into physics so that I can at least begin to understand the underlying principles involved.

Everything I have posted at this forum is related in some way to heating systems. A recent boiler change in my home produced some very strange anomolies of easily measurable magnitude.

Seeming simple questions like how radiation passes through window glass find (in my opinion) poor answers. I ask if a visible light photon passes through such or if it is absorbed on one surface and propagated out the other. Am told that it doesn't matter because the photons are indistinguishable. Only the apparent result matters, not the process? When we're talking about things that do not necessarily conform to our sense of time and space how (when the process is uncertain) can we be sure that the observable result is the only result?

I don't have a philosophic problem with light–I have a problem understanding photons.

Again, please tell me if I am making factual errors when I say that:

1) Light is a form of energy that travels via photons–just like radio photons, IR photons, etc. Our eyes just happen to be sensitive to energy in the frequency range of visible light.

2) Energy moves between bodies in waves–waves that vary in both amplitude and frequency.

3) This energy travels in discreet bundles at an immutable velocity regardless of how the waveform changes in our perception of length with amplitude and frequency.

4) This energy is always moving both ways between objects.

4) In some (and perhaps all) cases this waveform is not simple–it is composed of two distinct waves in direct opposition (at right angles to) one another.

4) We are immersed in a sea of energy that does not conform to our sense of time and distance.
 

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