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What are Baryon Resonances? 
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#1
Apr1614, 08:26 AM

P: 121

i've looked online and the closest i've found to a definition is this:
if someone could shed a little light on this it would be appreciated as there appears to be very little information on the internet that explains what a baryon resonance actually is or to what property the term 'resonance' actually refers. 


#2
Apr1614, 03:14 PM

P: 306

A resonance is, in general, a very short living particle. In particular, for such particles it's pretty hard to define an actual value of their mass and this is basically a consequence of the uncertainty principle. If the particle is very short living then:
$$ \Delta t\Delta E\sim\hbar\Rightarrow \Delta E\sim\frac{\hbar}{\Delta t}, $$ and the spread on its energy (rest mass) is very large. This particles are called resonances since they are so short living that they basically only appear as virtual states. Consider for example the scattering between two particles, say A and B: [itex]A+B\to A+B[/itex]. In QFT the cross section (i.e. more or less the probability) for this scattering to occur is the sum of all the possible Feynman diagrams that give you the same final state. Now, if the energy of the two particles is reasonably close to the mass of this unstable particle, say X, you have one addition channel for your scattering: [itex]A+B\to X\to A+B[/itex]. Of course this is possible only if the quantum numbers are the right ones. Then it turns out that right near the mass of this particle the scattering cross section as a function of the energy drastically increases (basically because of the presence of one additional channel) showing the typical resonant behavior. 


#3
Apr1614, 06:39 PM

P: 762

I guess the name resonance came in use because of how they appear in experiments....
They appear as peaks of the cross section with respect to energy.... There's also a more satisfying explanation, in case you are familiar with classical resonances... For example if you check the wikipedia for resonances (http://en.wikipedia.org/wiki/Resonance) and take a look at the "intensity of oscillations I" formula, you will see a familiar formula (Breit Wigner cross section which describes resonances). If you also read below the formula, it says that "The intensity is defined as the square of the amplitude of the oscillations" And how is the differential cross section given? It's the square of the scattering amplitude... You don't have any mechanical oscillation though... since the amplitudes of oscillations represent some mechanical motion, but the scattering amplitudes come from the interaction of the wavefunction with a local potential... [itex] \psi_{scatt}= e^{ikx} + \frac{e^{ikr}}{r}f(k,k')[/itex] http://en.wikipedia.org/wiki/Scattering_amplitude 


#4
Apr1714, 07:21 AM

P: 121

What are Baryon Resonances?
Excellent replies as always!! Thanks!!!



#5
May314, 11:46 AM

Sci Advisor
Thanks
P: 4,160

Here's a recent paper from the LCHb collaboration concerning their observations of a meson state, the Z_{1}^{}(4430). To address the essential question "is it a peak, or really a particle" they say, 


#6
May314, 08:34 PM

P: 762

@Bill K
what else could a peak be but a particle? I'm asking because as far as I know: peaks denote bound states... or semibound... depending on their branches... Bound states appear in general as resonances... 


#7
May414, 08:34 AM

Mentor
P: 11,631

Resonances are so shortliving that you often see interference effects  and then you are sensitive to the phases. For longliving intermediate particles, interference effects (in the decays via those particles) are negligible.



#8
May414, 09:58 AM

Sci Advisor
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P: 4,160

One possibility was a weakly bound "molecular" combination of two mesons. Another was a threshold effect, since its mass lies so close to the DD* threshold. See this paper, which says, 


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