How to Obtain g(x) from f(z) for a Given Equation and Distribution?

  • Thread starter zetafunction
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In summary, if f(x) is known for all complex x, then g(x) can be obtained from the difference f(x+i\epsilon ) - f(x-i\epsilon ). However, the reverse is not true, as adding any continuous function to f(z) would still result in the same g(x). This assumes that f(z) is discontinuous perpendicular to the real axis.
  • #1
zetafunction
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given any function (or maybe distribution) f(x) and g(x) so

[tex] f(x+i\epsilon ) - f(x-i\epsilon ) = g(x) [/tex]

if we know f(x) could we obtain g(x) from the difference above ??

if we knew g(x) could we solve the equation to get f(x) ??

here [tex] \epsilon \rightarrow 0 [/tex]
 
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  • #2
For the first question, if you know f(z) for all complex z, you can get g(x). For the second question the answer is no, since you can add any continuous function to f(z) and still get the same g(x).

I presume that f(z) is discontinuous perpendicular to the real axis, otherwise the question is trivial.
 

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