- #1
angel_eyez
- 19
- 0
Reimann's Law..maajoor Helpp!
1. Use Riemann sum ( do NOT use fundamental theorum of Calculus) to calculate
(integral) b= 1 and a =0 e^x dx
Attempt:
(delta x)=b-a/n 1-0/n =1/n
xi = 1/n
(integral) b=1 a=0 sigmaf(xi)deltax
limn->infin sigma f(i/n)1/n
use eqn to get...limn->infin 1/nsigma{e^(i/n)}
limn->infin 1/n e^1/ni
limn->infi 1/ne^1/n n(n+1)/2
limn->infin 1/n e^1/2(n+1)
then sub for n (table n | Rn where n =40,100,500,1000,5000 and Rn should be close to 1.72(got that using FTC2)...so the eqn must be wrong :D
3.
1. Use Riemann sum ( do NOT use fundamental theorum of Calculus) to calculate
(integral) b= 1 and a =0 e^x dx
Attempt:
(delta x)=b-a/n 1-0/n =1/n
xi = 1/n
(integral) b=1 a=0 sigmaf(xi)deltax
limn->infin sigma f(i/n)1/n
use eqn to get...limn->infin 1/nsigma{e^(i/n)}
limn->infin 1/n e^1/ni
limn->infi 1/ne^1/n n(n+1)/2
limn->infin 1/n e^1/2(n+1)
then sub for n (table n | Rn where n =40,100,500,1000,5000 and Rn should be close to 1.72(got that using FTC2)...so the eqn must be wrong :D
3.