- #1
jojo12345
- 43
- 0
I understand that there is a way to find a basis [tex]\{e_1,...,e_n\}[/tex] of a vector space [tex] V[/tex] such that a 2-vector [tex] A [/tex] can be expressed as
[tex] A = e_1\wedge e_2 + e_3\wedge e_4 + ...+e_{2r-1}\wedge e_{2r}[/tex]
where 2r is denoted as the rank of [tex]A[/tex]. However the way that I know to prove this seems sort of inelegant. I'm wondering what other proofs people have.
[tex] A = e_1\wedge e_2 + e_3\wedge e_4 + ...+e_{2r-1}\wedge e_{2r}[/tex]
where 2r is denoted as the rank of [tex]A[/tex]. However the way that I know to prove this seems sort of inelegant. I'm wondering what other proofs people have.