How do different theories of spacetime affect the concept of speed?

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Received 8 December 1978; accepted for publication 20 October 1979)In summary, the conversation discusses the relationship between spacetime and velocity, specifically in the context of a runner covering a distance in a certain amount of time. It is stated that different observers may measure different amounts of space and time for the same event, but the underlying principle remains the same. The concept of rapidity is introduced as a measure of velocity that takes into account the effects of relativity. It is also mentioned that the term "celerity" may be more appropriate in this context.
  • #1
Futobingoro
I have a quick question:

Does the arrangement of spacetime directly dictate rates like velocity?

For example, if it takes a man 10 minutes to run 2 kilometers, does that mean that there were 10 minutes of time and 2 kilometers of space between his starting and ending position?
 
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  • #2
No, different observers partition his trip into different amounts of space travel and time travel. The underlying principle is that, however you do this, the combination:

[tex] (c \Delta t)^2 - (\Delta x)^2 [/tex]

is the same for all (inertial) observers. So, for example, someone might be moving relative to the runner so that he appears to be moving faster and so cover more distance. That is, [itex]\Delta x[/itex] is larger that 10 km for them. But then in order to maintain the value of the above expression, [itex]\Delta t[/itex] would also have to increase, ie, they would observe the runner's watch to be running slow.
 
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  • #3
Not really. But the spacetime interval between the two events (the start and finish of the run) is the same in all frames. The space-part and time-part will differ based on who is making the measurements.

EDIT:Yes, what StatusX said. ;-)
 
  • #4
StatusX said:
the combination:

[tex] c^{\color{red}2} (\Delta t)^2 - (\Delta x)^2 [/tex]
(minor typo corrected)
 
  • #5
If the 2 km course is marked out by a stationary observer, and the time it takes the man to run the 2 km is measured by a watch that he carries around with him, the ratio distance / time is known as a "rapidity" rather than a velocity.

The difference between rapidity and velocity is that the time for the man to run the distance would be measured by clocks in the lab frame. Typically one would have one clock at the start of the course, one clock at the finish of the course, and the issue of synchronizing clocks arises. This could get rather detailed, so I'll just skip ahead a lot and say that the runner's time measured on the clock he carries with him according to relativity be shorter than the time reading measured in the lab frame that goes into the velocity equation.
 
  • #6
pervect said:
If the 2 km course is marked out by a stationary observer, and the time it takes the man to run the 2 km is measured by a watch that he carries around with him, the ratio distance / time is known as a "rapidity" rather than a velocity.

The standard definition of "rapidity" is that is the Minkowski-angle [tex]\theta[/tex] (the spacelike-arclength along the Minkowski-unit-circle), between two future unit-timelike vectors (along the "t"-axis of the stationary inertial observer and the "s"-axis of the inertial runner). Its hyperbolic-tangent yields the ordinary [spatial-]velocity [tex]v=c\tanh\theta[/tex] (the ratio of [instantaneous] spatial-displacement and temporal-displacement, i.e. ["opposite over adjacent"]).

Maybe the term you mean is "celerity" (coined by Levy-Leblond? see http://arxiv.org/abs/physics/0608040 )
which is "the spatial-part of the 4-velocity [tex]v^a[/tex]"
[tex]\gamma v=(\cosh\theta) (c\tanh\theta)= c\sinh\theta[/tex], i.e. ["opposite over hypotenuse"] . (A spacetime diagram would probably clarify this.)
 
  • #7
robphy said:
The standard definition of "rapidity" is that is the Minkowski-angle [tex]\theta[/tex]

You're right, I double-checked with
http://www.eftaylor.com/pub/spacetime/STP1stEdP41to59.pdf

Maybe the term you mean is "celerity" (coined by Levy-Leblond? see http://arxiv.org/abs/physics/0608040 )

A good reference, which I'd recommend to the OP, and some calculations show me the difference is important. Sorry for any confusion.

A celerity of 2 (covering 2 light years (lab frame) in 1 year (proper time)) is equivalent to a rapidity of 1.4436 via the Taylor & Wheeler definition, and a velocity of .8944 c, i.e. 2 light years (lab frame) in 2.236 years (lab time).
 
  • #8
Here is the Levy-Leblond article:
http://link.aip.org/link/?AJPIAS/48/345/1 [Broken]

American Journal of Physics -- May 1980 -- Volume 48, Issue 5, pp. 345-347

Speed(s)

Jean-Marc Lévy-Leblond
Laboratoire de Physique Théorique et Havtes Energies, Université Paris VII, Place Jussieu, 75221 Paris Cedex 05, France

Three simple distinct operational procedures are given for transforming the empirical notion of speed into a formal concept. While in the Galilean theory of space-time, the three quantities coincide with the customary velocity, they differ in the Einsteinian theory. In particular, it is shown that ''rapidity'' has a direct and natural physical meaning.
 
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1. What is spacetime?

Spacetime is a concept that combines the three dimensions of space (length, width, and height) with the dimension of time. It is a mathematical model used to describe the physical universe and how objects move through it.

2. How does an object move through spacetime?

An object moves through spacetime by following a path called a world line. This world line is influenced by the curvature of spacetime, which is caused by the presence of mass and energy.

3. Is time travel possible through spacetime?

According to Einstein's theory of relativity, time travel is theoretically possible by moving through spacetime at speeds close to the speed of light. However, this type of time travel is currently not achievable with our current technology.

4. What is the relationship between gravity and spacetime?

Gravity is not a force in itself, but rather a curvature in spacetime caused by the presence of mass and energy. Objects with more mass create a stronger curvature in spacetime, which is why they have a stronger gravitational pull.

5. How does the understanding of spacetime impact our understanding of the universe?

The concept of spacetime has revolutionized our understanding of the universe, allowing us to explain and predict the movement of objects on a large scale. It also helps us understand the effects of gravity and how it relates to the structure and formation of the universe.

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