- #1
seeker101
- 28
- 0
Does anyone have any suggestions on how to go about proving that
[tex]\left\lceil\frac{1}{2}{\lceil \log m\rceil}^2\right\rceil[/tex] is less than m-1, for m > 64? (using log to the base 2)
[tex]\left\lceil\frac{1}{2}{\lceil \log m\rceil}^2\right\rceil[/tex] is less than m-1, for m > 64? (using log to the base 2)