Josephson Effect: AC vs. DC Explained

  • Thread starter abhaymv
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In summary: I didn't know that they related to the same phenomenon.The DC and AC Josephson "effects" are more or less just the name of the two Josephson equations, they are not really separate phenomena.The DC Josephson effect (tehj 1st equation) tells you that the current through the junction depends on the phase difference across it, and the AC Josephson effect (the 2nd equation) relates the voltage across the junction depends to the time derivative of the phase.Just to be clear on this,DC josephson effect:Occurs when there is no ptential difference,and cuttent varies between -I to IAC Josephson effect:Occurs when the applied potential crosses
  • #1
abhaymv
9
0
Hello,
What exactly is the difference between ac Josephson Effect and DC Jsephson effect?When does each occur?What is the relevence of magnetic field here?In which cases are potentials applied?I tried to find the answer in the net,but couldn't find any satisfactory explanations.I have not begun to study quantum mechanics in detail.Can someone help me?Please explain in simple terms.

PS:Equations are not very important as far as I am concerned.I just want to get an idea about the phenomenon.
 
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  • #2
This sounds a bit like homework. Your questions are quite general but the answers are easy to find.
Have you tried looking in a textbook? E.g. Tinkham or Waldram.

Btw. You don't really need QM at all in order to understand the answers to your questions, simple circuit models will do.
 
  • #3
f95toli said:
This sounds a bit like homework. Your questions are quite general but the answers are easy to find.
Have you tried looking in a textbook? E.g. Tinkham or Waldram.

Btw. You don't really need QM at all in order to understand the answers to your questions, simple circuit models will do.

Its not homework.I didn't understand the lecture in my class.I have only bits of info.I think by what I understand,
Both phenomenon occur when two superconductors are separated by an extremely thin insulator.
Also that electons penetrate the insulators in pairs called cooper pairs.

But I cannot understand the distinction between the processes.I tried a textbook,but it gives a vague answer in terms of quantum mechanics,in relation with something called a SQUID.
 
  • #4
The DC and AC Josephson "effects" are more or less just the name of the two Josephson equations, they are not really separate phenomena.
The DC Josephson effect (tehj 1st equation) tells you that the current through the junction depends on the phase difference across it, and the AC Josephson effect (the 2nd equation) relates the voltage across the junction depends to the time derivative of the phase.

Look at e.g the wiki for the Josephson effect.
 
  • #5
f95toli said:
The DC and AC Josephson "effects" are more or less just the name of the two Josephson equations, they are not really separate phenomena.
The DC Josephson effect (tehj 1st equation) tells you that the current through the junction depends on the phase difference across it, and the AC Josephson effect (the 2nd equation) relates the voltage across the junction depends to the time derivative of the phase.

Look at e.g the wiki for the Josephson effect.

Thank you.I didn't know that they related to the same phenomenon.
 
  • #6
f95toli said:
The DC and AC Josephson "effects" are more or less just the name of the two Josephson equations, they are not really separate phenomena.
The DC Josephson effect (tehj 1st equation) tells you that the current through the junction depends on the phase difference across it, and the AC Josephson effect (the 2nd equation) relates the voltage across the junction depends to the time derivative of the phase.

Look at e.g the wiki for the Josephson effect.

Just to be clear on this,
DC josephson effect:Occurs when there is no ptential difference,and cuttent varies between -I to I
AC Josephson effect:Occurs when the applied potential crosses a critical potential,Vc

I am still unclear about what occurs in between the time when a small potential is applied,and then it rises to Vc..

Please tell me where I am wrong.

Also,in the derivation of DC josephson tunnelling,

we see:
i(h/2π)(∂φ/∂t)=Eφ

But,when applied to electron probability density in semiconductor 1,this becomes:
i(h/2π)(∂φ1/∂t)=(h/2π)Tφ2
where T is the tunnelling frequency.

IS Eφ1 equal to (h/2π)Tφ2?
(We just studied the derivation,an explanation was not given..)

Also, in the derivation of AC josephson effect,there is an extra term -eVφ1.
Where V is the potential.
Wy is the potential term subtracted?Doesn't the potential support the flow of electron pairs across the junction?
 
  • #7
An easy explanation can be found also in the "Feynman Lectures".
 
  • #8
Thank you
 

1. What is the Josephson Effect?

The Josephson Effect is a phenomenon in superconductors where an electric current can flow without any resistance, even in the absence of an applied voltage.

2. What is the difference between AC and DC Josephson Effect?

In AC Josephson Effect, the electric current oscillates back and forth between two superconductors at a specific frequency, while in DC Josephson Effect, the current remains constant.

3. How does the Josephson Effect contribute to technology?

The Josephson Effect has many practical applications, including highly precise measurements of frequency and voltage, as well as the development of superconducting quantum interference devices (SQUIDs) which are used in MRI machines and other sensitive instruments.

4. What is the significance of the Josephson Constant?

The Josephson Constant, also known as the Josephson frequency, is a fundamental physical constant that relates to the frequency of the AC Josephson Effect. It is used in many scientific calculations and measurements.

5. Can the Josephson Effect occur in any material?

No, the Josephson Effect only occurs in superconducting materials, which are materials that can conduct electricity without any resistance when cooled to very low temperatures.

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