Help me Understand Closed Under Addition and Closed Under Multiplication

In summary, "closed under addition" means that the sum of any two members of a set is also in the set, while "closed under multiplication" means that the product of any member and a scalar is also in the set. Examples of sets that are closed under addition are the set of even integers, while an example of a set that is closed under multiplication is the set of 2 x 2 diagonal matrices. In linear algebra, sets are often considered in terms of their closure under addition and multiplication, as shown in the examples of subsets of \mathbb{R}^2.
  • #1
nicknaq
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Help me Understand "Closed Under Addition" and "Closed Under Multiplication"

Linear Algebra...matrices...etc

Examples would be great.

Thanks.
 
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  • #2


A set is "closed under addition" if the sum of any two members of the set also belongs to the set. For example, the set of even integers. Take any two even integers and add them together. The result is an even integer.

A set is "closed under (scalar) multiplication" if the product of any member and a scalar is also in the set. In other words, if x is in S and a is any scalar then ax will be in the set if the set is closed under scalar multiplication. For example, the set of 2 x 2 diagonal matrices is closed under scalar multiplication.
 
  • #3


Not sure what you want here, but I'll give it a shot.
In the following, we will consider following subsets of [tex]\mathbb{R}^2[/tex]:

[tex]A=\{(x,y)~\vert~y=0\}~\text{and}~B=\{(x,y)~\vert~x+y=1\}[/tex]

Typical elements of A are (1,0), (2,0),... The element (1,1) is an element not in A.
Typical elements of B are (1,0), (1/2,1/2),... The element (1,1) is an element not in B.

Now A and B carry an addition (i.e. (x,y)+(x',y')=(x+y,x'+y')). Saying that A is closed under addition just means that whenever you take two elements in A, the sum of those elements is again in A. Let's check if this is the case: two elements in A have the form (x,0) and (x',0). The sum of those elements is (x+x',0), and this is again in A. Thus A is closed under addition.

But B is not closed under addition. For example, the element (1,0) is in B. But (1,0)+(1,0)=(2,0) and this sum is not in B. Thus the sum of two elements in B is not necessarily in B. Thus B is not closed under addition.

Closed under multiplication just means that, whenever you take [tex]\alpha\in \mathbb{R}[/tex] and (x,0) in A, we have that [tex]\alpha (x,0)[/tex] is back in A. And this is indeed the case. Thus A is closed under multiplication.
B, on the other hand, is not closed under multiplication, can you see why?
 

What does it mean for a set to be "closed under addition"?

When a set is closed under addition, it means that when you add any two elements from the set together, the result will also be an element in the set. In other words, the set contains all possible sums of its elements.

What is an example of a set that is closed under addition?

An example of a set that is closed under addition is the set of even numbers. When you add any two even numbers together, the result will always be an even number, which is also an element in the set.

Can a set be closed under addition but not closed under multiplication?

Yes, a set can be closed under addition but not closed under multiplication. For example, the set of positive integers is closed under addition, but when you multiply two positive integers together, the result may not be a positive integer.

How do you prove that a set is closed under multiplication?

To prove that a set is closed under multiplication, you need to show that when you multiply any two elements in the set together, the result will also be an element in the set. This can be done using mathematical induction or by directly showing that all possible products are in the set.

Why is it important for a set to be closed under addition and multiplication?

It is important for a set to be closed under addition and multiplication because it allows for consistent and predictable results when performing mathematical operations on the set's elements. It also makes it easier to manipulate and solve equations involving the set's elements.

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