Number of electrons in a surface state

[oplendr]

Dear all,

Im trying to reproduce a calculation of number of electrons in a surface state given in Bertel/Surf.Sci.367 (1996)L61/ and getting a bit confuse since the numbers coming out are totally wrong.

In the paper, the surface state of Pt(111) surface is considered. Authors write

"On clean Pt(111) the surface state band
disperses with an effective mass of m* = 1.3 me. The
binding energy at F (center of the surface Brillouin
zone) is E_B(F)=400 meV. Consequently the
surface state band contains 0.14 electrons per sur-
face atom."

To calculate this 0.14 electrons, I take the total density of states in 2D Fermi gas as (1.3*me*E_B)/(Pi*h^2) which gives 0.35 kg/eV/s^2. What should be done then? Multiply by unit cell area?

 

[BigJDubs]

Thanks in advance. Regards,Yes, you should multiply the total density of states by the unit cell area to get the total number of electrons in the surface state. Then you can divide this number by the total number of surface atoms in the unit cell to get the number of electrons per surface atom.