- #1
Philip Wong
- 95
- 0
I was asked to help someone to work out the probability above. It was more than a year since I done similar questions and thing do get rusty... So I hope to work it out here and get point out where I did wrong before I show that person the correct answer.
Intuitively there is three ways I came up to solve the problem, which apparently gave different answers. So it's either one or two or all three methods are wrong. Methods I came to mind are:
1) 1/6 * 1/6 * 5/6 = 0.023 -> this is the first idea came to my mind, since there is only 3trials and the probability of getting a 6 is 1/6, so I use the multiply rule to times things together. The results seems rather small, so I doubt this is the correct method.
2) 3C2 * 1/6 * (5/6)^2 = 0.347 -> I got this by using the binomial equation
3) 3C2 * 1/6 * 5/6 = 0.416 -> I got this by using the Bernoulli equation i.e. n*p*q. where n is the number of all possible outcomes, p is the probability of getting a 6, and q is the probability of not getting a 6.
Please check which methods I used was correct, and if neither of them was correct please suggest a way to work this out.
Intuitively there is three ways I came up to solve the problem, which apparently gave different answers. So it's either one or two or all three methods are wrong. Methods I came to mind are:
1) 1/6 * 1/6 * 5/6 = 0.023 -> this is the first idea came to my mind, since there is only 3trials and the probability of getting a 6 is 1/6, so I use the multiply rule to times things together. The results seems rather small, so I doubt this is the correct method.
2) 3C2 * 1/6 * (5/6)^2 = 0.347 -> I got this by using the binomial equation
3) 3C2 * 1/6 * 5/6 = 0.416 -> I got this by using the Bernoulli equation i.e. n*p*q. where n is the number of all possible outcomes, p is the probability of getting a 6, and q is the probability of not getting a 6.
Please check which methods I used was correct, and if neither of them was correct please suggest a way to work this out.