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converting input in rlc circuits

 
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Dec18-12, 03:32 AM   #1
 

converting input in rlc circuits


I was wondering how to convert E=70.7sinwt..<-- (just an example)
to something like 50∠0 degrees?
 
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Dec19-12, 07:19 AM   #2
 
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Hi VerdictGuilty,


E=70.7sin(Ѡt + 10°)
=70.7∠10°

Too easy!
 
Dec19-12, 07:24 AM   #3
 
You're converting it to phasor representation. You want to employ Euler's identity to convert the sinusoid to a complex number from which you can obtain the modulus(magnitude) and phase.
 
Dec19-12, 11:38 AM   #4
 

converting input in rlc circuits


@NascentOxygen,

Since the phase angle is based on the cosine function, are you missing a -90deg factor in your answer? should it be 70.7∠-80?
 
Dec20-12, 08:20 PM   #5
 
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Quote by jrive View Post
@NascentOxygen,

Since the phase angle is based on the cosine function, are you missing a -90deg factor in your answer? should it be 70.7∠-80?
I referenced it to a sine wave.
 
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