- #1
ILoveBaseball
- 30
- 0
Consider the parametric curve given by the equations
[tex]x(t) = t^2+30t-11[/tex]
[tex]y(t)=t^2+30t+38[/tex]
How many units of distance are covered by the point P(t) = (x(t),y(t)) between t=0, and t=9 ?
well since the bounds are already given (0->9), i just need help on setting up the integral. here's what i done:
[tex]dx/dt = 2t+30[/tex]
my integral:
[tex]\int_{0}^{9}(t^2+30t+38)*(2t+30)[/tex]
but i get the incorrect answer when i integral it, can someone help me set it up?
[tex]x(t) = t^2+30t-11[/tex]
[tex]y(t)=t^2+30t+38[/tex]
How many units of distance are covered by the point P(t) = (x(t),y(t)) between t=0, and t=9 ?
well since the bounds are already given (0->9), i just need help on setting up the integral. here's what i done:
[tex]dx/dt = 2t+30[/tex]
my integral:
[tex]\int_{0}^{9}(t^2+30t+38)*(2t+30)[/tex]
but i get the incorrect answer when i integral it, can someone help me set it up?