## Projectile Motion

1. The problem statement, all variables and given/known data

Find the angle of the projection for which the maximum height is equal half of the range.

2. Relevant equations

Kinematic and Projectile motion equations
 Just use SUVAT equations.
 I'm working on the same problem. Any help would be appreciated. I've gotten as far as finding R(range)= (Vo^2sin2Theta)/g but how do I find the formula for Max height?

## Projectile Motion

 Quote by LadyMario I'm working on the same problem. Any help would be appreciated. I've gotten as far as finding R(range)= (Vo^2sin2Theta)/g but how do I find the formula for Max height?
$R(range)= \frac{Vo^2 Sin2\Theta}{g}$

For maximum height
(v0Sinθ)2=2aR
 How did you get that equation for max height?

 Quote by LadyMario How did you get that equation for max height?
(vy)2=(uy)2-2as
 Thank you so much :)!
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