Projectile Motion

McDonell

1. The problem statement, all variables and given/known data

Find the angle of the projection for which the maximum height is equal half of the range.

2. Relevant equations

Kinematic and Projectile motion equations

azizlwl

Just use SUVAT equations.

LadyMario

I'm working on the same problem. Any help would be appreciated. I've gotten as far as finding R(range)= (Vo^2sin2Theta)/g but how do I find the formula for Max height?

azizlwl

Quote by LadyMario

I'm working on the same problem. Any help would be appreciated. I've gotten as far as finding R(range)= (Vo^2sin2Theta)/g but how do I find the formula for Max height?

[itex]R(range)= \frac{Vo^2 Sin2\Theta}{g}[/itex]

For maximum height
(v₀Sinθ)²=2aR

LadyMario

How did you get that equation for max height?

azizlwl

Quote by LadyMario

How did you get that equation for max height?

(v_y)²=(u_y)²-2as

LadyMario

Thank you so much :)!

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McDonell	Projectile Motion Tweet 1. The problem statement, all variables and given/known data Find the angle of the projection for which the maximum height is equal half of the range. 2. Relevant equations Kinematic and Projectile motion equations

LadyMario	I'm working on the same problem. Any help would be appreciated. I've gotten as far as finding R(range)= (Vo^2sin2Theta)/g but how do I find the formula for Max height?