Register to reply 
Gravtational Potential energy 
Share this thread: 
#1
Feb1814, 08:00 PM

P: 71

When a rocket is launched into space, its GPE increases and its KE decreases.
If we equate the change in both energies we can find out the velocity of the rocket at a certain height. Δ GPE = Δ KE Does the equation already take the opposing gravitational force of earth into account? 


#2
Feb1814, 08:08 PM

Sci Advisor
Thanks
P: 3,760




#3
Feb1814, 08:21 PM

P: 71

Isnt GPE the work done in bringing a mass from infinity to a point inside a particular gravitational field?



#4
Feb1814, 08:51 PM

Sci Advisor
Thanks
P: 3,760

Gravtational Potential energy
You are thinking of the very useful and widely used convention in which we choose to assign zero to the potential energy at infinity. Then the PE at any other point is, as you say, the (negative of) the work done on bringing a mass in from infinity. However, we could just as reasonably choose to assign zero potential to a point at the surface of the earth, and this choice makes the calculations easier if you're working with a rocket launched from the surface of the earth. 


#5
Feb1814, 10:08 PM

P: 71

Does changing the position of zero position change the formula of GPE?



#6
Feb1814, 11:33 PM

Mentor
P: 11,787

Yes. If we define GPE = 0 at r = ∞, then
$$GPE = \frac{GMm}{r}$$ where M is the mass of the earth, m is the mass of the object in question, and r is the distance from the center of the earth. (This applies only above the surface of the earth) If we define GPE = 0 at r = R, where R is the radius of the earth, then $$GPE = GMm \left( \frac{1}{R}  \frac{1}{r} \right)$$ You should be able to check for yourself that both formulas give the same result for ΔGPE between two different values of r. 


#7
Feb1914, 03:01 AM

P: 71

In this case of rocket launch what force is doing work?



#8
Feb1914, 03:24 AM

Sci Advisor
Thanks
P: 3,760




#9
Feb1914, 03:29 AM

P: 71

So can the potential energy of the rocket can be calculated by the formula
(Thrust  Gravitational force) * distance In my book the gain in GPE of the rocket is calculated by GMm/r which basically came from integrating Gravitational force* distance Is there any difference? I am really confused in the case of rocket launching 


#10
Feb1914, 05:55 AM

P: 965

Potential energy applies when the work it takes to reach a certain position against a particular force does not depend on the path you take to get there. Gravity has this property. Gravitational force is a "conservative field". So it makes sense to talk about the potential energy of gravity. Thrust does not have this property. So it does not make sense to talk about the potential energy of thrust.



Register to reply 
Related Discussions  
Gravtational Potential Energy  Introductory Physics Homework  4  
Gravitational Potential Energy, Elastic Potential Energy, and Kinetic Energy  Introductory Physics Homework  3  
Electric potential energy and gravitational potential energy of Deuterium nuclear?  High Energy, Nuclear, Particle Physics  1  
Electric potential energy and gravitational potential energy of Deuterium nuclear?  Advanced Physics Homework  1  
Gravtational Potential Energy  Introductory Physics Homework  10 