Exploring the Effect of k on the Wave and its Physical Significance

In summary, the problem discusses the angular frequency of a light wave represented by e^iw(t-nx/c) and mentions that n can sometimes be replaced by the complex quantity n-ik. The question then asks about the effect of k on the wave and its physical significance. By substituting n-ik for n and multiplying in the iw, the exponent becomes e^(iwt-iwnx +kx)/c. This shows that the k term is the only real term in the exponent and results in a dampened wave. The larger the k value, the quicker the wave dies.
  • #1
Wishbone
139
0
The problem gives the angular frequency of a light wave (w) is represented by


e^iw(t-nx/c)

it says that sometimes n is replaced by the complex quantity n-ik.

The question asks what is the effect of k on the wave. Also, it asks, what is its physical signifigance?


I tried substituting in for n-ik for n, and then multiplying in the iw.


I got: e^ (iwt-iwnx +kx)/c

So I see that the k term is the only real term in the exponent, however I am not sure how that effects the wave, or what its physical signifigance is.
 
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  • #2
I don't think that is correct. Doing the calculations, I get, after putting into an illuminating form:

[tex]e^{-kx/c}e^{i(wt-nx/c)}[/tex]

What kind of a wave is that? (i.e. what is the effect of k on the wave?)
 
  • #3
thats a dampened wave, isn't it?
 
  • #4
and the larger the K, the quicker the wave dies?
 
  • #5
yep.

------
 
  • #6
sweet, thanks dude.
 

1. What is the significance of the variable "k" in the wave equation?

K represents the wave number, which is a measure of the number of complete waves in a given distance. It is related to the wavelength of the wave, with a higher k value corresponding to a shorter wavelength. K also affects the energy and speed of the wave.

2. How does changing the value of k impact the shape of a wave?

As mentioned before, k is related to the wavelength of the wave. Therefore, changing the value of k will cause the wavelength to either increase or decrease, which in turn affects the shape of the wave. A higher k value will result in a shorter wavelength and a more compact wave, while a lower k value will result in a longer wavelength and a more spread out wave.

3. How does k affect the energy of a wave?

K is directly proportional to the energy of a wave. This means that as the value of k increases, so does the energy of the wave. This is because a higher k value indicates a shorter wavelength, which requires more energy to maintain the wave's amplitude.

4. How is the physical significance of k demonstrated in real-world scenarios?

In real-world scenarios, k can be used to describe various physical phenomena such as the propagation of electromagnetic waves, the behavior of sound waves, and the motion of particles in a wave-like pattern. For example, in optics, k is used to calculate the refractive index of a material, which determines how light waves will bend when passing through it.

5. How do scientists manipulate k in experiments to understand its effect on waves?

Scientists can manipulate k in experiments by changing the properties of the medium through which the wave is passing. This can include changing the density, temperature, or composition of the medium. They can also use different equipment to measure and control the value of k in the wave equation. By manipulating k, scientists can observe how it affects the propagation, energy, and behavior of waves in different mediums.

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