- #1
Taryn
- 63
- 0
Hey I have been having a lot of trouble in solving these problems and I have exams soon and I really don't know where to start, I know u aint meant to give the answers so instead would someone please go through all of the steps to finish this!
I really need some kinda help, This question was in a quiz and I was so confused as to wat I needa do... I am going to get help from a lecturer as well but inorder to study it I need some help please.
A buffer solution of pH = 5.30 can be prepared by dissolving acetic acid and sodium acetate in water. How many moles of sodium acetate must be added to 1.0 L of 0.25 M acetic acid to prepare the buffer?
The answer is meant to be 0.90mol but I have no Idea how to get to that!
Also one more We mix 100 mL of 0.20 M HBr and 50.0 mL of 0.40 M NaC1O. What is the pH of the resulting solution? Ka(HC1O) = 3.5 x 10-8
for this one i Wrote out the equation... and found that the concentration of HClO was 0.1333 or something like that... then I just had no idea where to go from there, I no that pH=pka- log(acid/base) but I just didnt no how to get to that point... I changed Ka(HClO) to pKa by using -log3.5 x 10- 8 but as I sed not sure where to go.
Could anyone please help
I really need some kinda help, This question was in a quiz and I was so confused as to wat I needa do... I am going to get help from a lecturer as well but inorder to study it I need some help please.
A buffer solution of pH = 5.30 can be prepared by dissolving acetic acid and sodium acetate in water. How many moles of sodium acetate must be added to 1.0 L of 0.25 M acetic acid to prepare the buffer?
The answer is meant to be 0.90mol but I have no Idea how to get to that!
Also one more We mix 100 mL of 0.20 M HBr and 50.0 mL of 0.40 M NaC1O. What is the pH of the resulting solution? Ka(HC1O) = 3.5 x 10-8
for this one i Wrote out the equation... and found that the concentration of HClO was 0.1333 or something like that... then I just had no idea where to go from there, I no that pH=pka- log(acid/base) but I just didnt no how to get to that point... I changed Ka(HClO) to pKa by using -log3.5 x 10- 8 but as I sed not sure where to go.
Could anyone please help