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A little stoichiometry...
Here's all that was given:
A container of HCl spilled on a marble table surface. The marble contains calcium carbonate, which reacts with the acid to produce calcium chloride, carbon dioxide and water.
a) If 500ml of 0.2 M acid spilled, what mass of calcium carbonate reacted?
So I wrote out the (combustion is it?) equation.
[tex]CaCO_3 + 2HCl\rightarrow CaCl_2 + CO_2 + H_2O[/tex]
Then molar mass:
[tex]100g(CaCO_3) + 72g(2HCl)\rightarrow 110g(CaCl_2) + 44g(CO_2) +18g( H_2O)[/tex]
So now I know that 72g of HCl is 2 mol (since 2HCl) so 0.2 mol = 7.2g
But know I'm stuck...a push in the right direction?
Also.
b)How many moles of [itex]CO_2[/itex] were formed during this reaction?
1 mole
c)How many molecules of water were formed during this reaction?
~6.022*10^23
I don't think there's any problems there.
Thanks in advance
Here's all that was given:
A container of HCl spilled on a marble table surface. The marble contains calcium carbonate, which reacts with the acid to produce calcium chloride, carbon dioxide and water.
a) If 500ml of 0.2 M acid spilled, what mass of calcium carbonate reacted?
So I wrote out the (combustion is it?) equation.
[tex]CaCO_3 + 2HCl\rightarrow CaCl_2 + CO_2 + H_2O[/tex]
Then molar mass:
[tex]100g(CaCO_3) + 72g(2HCl)\rightarrow 110g(CaCl_2) + 44g(CO_2) +18g( H_2O)[/tex]
So now I know that 72g of HCl is 2 mol (since 2HCl) so 0.2 mol = 7.2g
But know I'm stuck...a push in the right direction?
Also.
b)How many moles of [itex]CO_2[/itex] were formed during this reaction?
1 mole
c)How many molecules of water were formed during this reaction?
~6.022*10^23
I don't think there's any problems there.
Thanks in advance