Electromagnetic induction problem

In summary, a circular loop with a resistance of 0.5 Ω per meter of length is placed in a magnetic field of induction 2 Teslas. The loop's radius increases according to the equation r(t)=vt with v=0.5 m/s. The induced voltage at t=10 s can be found using either the Lorentz force method or Faraday's law method. Using the Lorentz force method, the induced voltage is found to be 31.416 Volts. Using the Faraday's law method, the induced voltage is found to be B*vt*(2*r0+vt)*π, where r0 is the original radius of the loop at t=0. However, if the
  • #1
kontejnjer
72
21

Homework Statement


A circular loop with resistance 0.5 [tex]\Omega[/tex] per meter of length is placed in a homogeneous magnetic field of induction B=2 Teslas. The magnetic field is perpendicular with the surface of the loop, as shown in the picture (image1). The radius of the loop is increasing according to the equation [tex] r(t)=vt[/tex] with [tex]v=0.5 m/s[/tex]. What is the induced voltage at time [tex]t=10 s[/tex]?

Homework Equations


U=Change in magnetic flux/change in time

The Attempt at a Solution


Well, it seems to me there are two ways of solving this problem: the Lorentz force method and Faraday's law method. I'll start with the Lorentz force method.

If we consider the fact that every part of the loop expands at the same rate, we can use the right hand rule for Lorentz force and find that the velocity of each part of the wire (and hence every electron) is perpendicular to the magnetic field, so:
[tex]Fm=Q*v*B[/tex]
At the same time, an electric field is generated by the stationary protons that is trying to pull the electrons back into place:
[tex]Fe=E*Q[/tex]
In the equilibrium position, the total force on the electrons will be zero:
[tex]EQ=Q*v*B[/tex]
And from this we get:
[tex]E=B*v[/tex]
Since:
[tex]E=U/d[/tex]
We obtain:
[tex]U=B*v*d[/tex]
Where d in this case is the circumference of the loop, so we plug that in and get:
[tex]U=2*r*B*v*\pi[/tex]
Since the radius changes with time, we plug that in as well:
[tex]U=2*v*t*B*v*\pi[/tex]
Since everything here is known, we put in all the values and get:
[tex]U=31.416 Volts[/tex]

Which is the correct answer according to the book (although I haven't really figured out for what purpose do I need the resistance per length value...).

The trouble I'm having is getting the other method to work properly.
I'm guessing the loop has an original non-zero size, so I'm going to use [tex]r_{0}[/tex] as that. At time [tex]t=0[/tex] the surface of the loop is:
[tex]S_{0}=r_{0}^{2}*\pi[/tex]
However, with time the radius gets larger:
[tex]r=r_{0}+vt[/tex]
Hence the surface gets larger as well:
[tex]S=r^{2}*\pi[/tex]
Since the surface of the loop changes, so does the magnetic flux:
[tex]\Delta\Phi=B*(S-S_{0})[/tex]
Or:
[tex]\Delta\Phi=B*((r_{0}+vt)^{2}-r_{0}^{2})*\pi[/tex]
Solving this as a difference of two squares:
[tex]\Delta\Phi=B*((r_{0}+vt-r_{0})*(r_{0}+vt+r_{0}))*\pi[/tex]
[tex]\Delta\Phi=B*vt*(2*r_{0}+vt)*\pi[/tex]

So this is the part I don't follow: how am I supposed to use this method if the original radius is not specified? If I set it to be zero at time [tex]t=0[/tex] then I get half of the correct value. Am I missing something here?

P.S. Sorry if I made any latex errors, it took me quite a while to write all of this.

EDIT: Forgot to put the image in the attachment, think it works now.
 

Attachments

  • image1.JPG
    image1.JPG
    14.3 KB · Views: 425
Last edited:
Physics news on Phys.org
  • #2
Anyone?
 

What is electromagnetic induction?

Electromagnetic induction is the process of generating an electric current in a conductor by moving it through a magnetic field or by changing the magnetic field around it.

What is the principle behind electromagnetic induction?

The principle behind electromagnetic induction is Faraday's law, which states that a changing magnetic field induces an electric field, which in turn causes a flow of electric current.

What are some real-world applications of electromagnetic induction?

Electromagnetic induction is widely used in many everyday devices, such as generators, transformers, and electric motors. It is also used in wireless charging technology, induction cooktops, and magnetic levitation trains.

What factors affect the strength of the induced current in electromagnetic induction?

The strength of the induced current depends on the strength of the magnetic field, the speed of the movement or change in the magnetic field, and the number of turns in the conductor.

How is electromagnetic induction related to the concept of self-inductance?

Self-inductance is a property of a conductor that causes it to resist any changes in the current flowing through it. It is related to electromagnetic induction because a changing current in a conductor can also induce a voltage in the same conductor, leading to self-inductance.

Similar threads

  • Introductory Physics Homework Help
Replies
7
Views
390
  • Introductory Physics Homework Help
Replies
1
Views
698
  • Introductory Physics Homework Help
Replies
4
Views
875
  • Introductory Physics Homework Help
Replies
5
Views
2K
  • Introductory Physics Homework Help
Replies
3
Views
552
  • Introductory Physics Homework Help
Replies
4
Views
554
  • Introductory Physics Homework Help
Replies
7
Views
841
  • Introductory Physics Homework Help
Replies
9
Views
1K
  • Introductory Physics Homework Help
Replies
7
Views
705
  • Introductory Physics Homework Help
Replies
2
Views
1K
Back
Top