- #1
airforce840
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Suppose that a projectile is launched from an initial height yi with an initial speed Vi and it strikes a target at a fianl height yf and fianl position xf. Show that the proper launch angle (feta symbol) is given by
feta = tan^-1 [xf +/- Square root of Xf^2 - 4k(k-Delta y) / 2K]
where K = ayXf^2/ 2 Vi^2
sry for the HORRIBLE typing of formulas..i don't know how to add them in.
and i don't have a photocopier.
thanks in advanced for any help on this one.
Patrick
feta = tan^-1 [xf +/- Square root of Xf^2 - 4k(k-Delta y) / 2K]
where K = ayXf^2/ 2 Vi^2
sry for the HORRIBLE typing of formulas..i don't know how to add them in.
and i don't have a photocopier.
thanks in advanced for any help on this one.
Patrick