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Formula for missing person's weight from team of 5 
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#19
Jul1914, 02:50 PM

Mentor
P: 12,023

@20GT: They could assume that the weight of X at the start is the same as the average of the others, then
(summed weight loss) = 4/5 * (starting weight of 5)  (final weight of 4) I don't see reasonable other assumptions. @disregardthat: I don't think it is reasonable. If X is heavier than average, you get a lot of imaginary weight loss (formula gives a large result without actual weight loss of anyone). 


#20
Jul2014, 08:53 AM

Sci Advisor
P: 1,810

It is more likely he he closer to the average of his group than the average of everyone since he participated in his groups initial weigh in.



#21
Jul2014, 11:29 AM

Mentor
P: 12,023

That makes it 20% less bad (as 20% of the weight* in the average comes from him), but still problematic.
*the mathematical weight, not the one in kg. 


#22
Jul2114, 03:04 AM

P: 10

Thanks everyone



#23
Jul2114, 03:08 AM

P: 10

He was taller and fatter than the rest.
2 normal looking weights 1 short fat person 1 short stocky person 


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