Does Anybody Know How to Name the IUPAC of these Compounds

[Fractal314]

Homework Statement

Does anyone know how to name these? I know how to name ethers when there is only one but these are just insane. IUPAC of course.

Homework Equations

1. O
||
CH3-CH2-O-CH=CH-CH-O-CH2-C-C-COOH
| ||
OH O

2. I O O
| || ||
O=C-C=C-CH2-CH-CH=CH-O-C-C-C-O-COOH
| | | ||
H OH OH O

The Attempt at a Solution

See I just don't know how to do multiple ethers here. And in the second one, is there an ester there or does the carboxylic acid take priority anyways?

Note: This can only be answered by people who can edit my post because for some reason the spaces do not show up properly when viewed. But if you go to edit this post it looks ok, so thanks for any help

 

[Borek]

I thought they will look better as CODE, but it didn't work either.

Try to download ACD/ChemSketch - they have free version. You will be able to draw a molecule and export it as a picture.

 

[Blueshift5]

with that!Hi there,

I am familiar with the IUPAC naming system for organic compounds. I can definitely help you with naming these compounds.

For the first compound, the correct IUPAC name is 2-ethoxy-3-(2-ethoxyethoxy)propanoic acid. Let's break it down:

- The main chain has 7 carbon atoms, so the prefix for this is "hept".
- The functional group is a carboxylic acid, which is indicated by the suffix "-oic acid".
- The first substituent is an ethyl group, so it is named as "ethoxy-" and attached to the second carbon atom of the main chain.
- The second substituent is a chain of two carbon atoms, attached to the third carbon atom of the main chain. This is an ethoxy group, so it is named as "ethoxy-" and the prefix for two is "di", making it "diethoxy-".
- The remaining four carbon atoms in the main chain are named as "propanoic acid".

For the second compound, the correct IUPAC name is (2Z,4E)-5-(2-ethoxyethoxy)-2,4-decadienoic acid. Let's break it down:

- The main chain has 10 carbon atoms, so the prefix for this is "dec".
- The functional group is a carboxylic acid, which is indicated by the suffix "-oic acid".
- The first substituent is a carboxylic acid, which takes priority over the alkene group. This is indicated by the prefix "carboxy-", making it "carboxy-".
- The alkene group has two double bonds, one at the second carbon atom and the other at the fourth carbon atom. This is indicated by the prefixes "2Z" and "4E".
- The second substituent is a chain of two carbon atoms, attached to the fifth carbon atom of the main chain. This is an ethoxy group, so it is named as "ethoxy-" and the prefix for two is "di", making it "diethoxy-".
- The remaining four carbon atoms in the main chain are named as "decadienoic acid".

I hope this helps! Let me know if you have any further questions.