- #1
thereddevils
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- 0
This is part of the identity proving question .
from [tex]\sin C=\frac{2}{\sqrt{29}}[/tex] , how can i reach [tex]C=\frac{1}{2}\sin^{-1} (\frac{20}{29})[/tex] ?
from [tex]\sin C=\frac{2}{\sqrt{29}}[/tex] , how can i reach [tex]C=\frac{1}{2}\sin^{-1} (\frac{20}{29})[/tex] ?