Nov23-13, 11:35 AM
Sorry I can't get latex working so bear with me as I am new to it. I start A-level physics in a week and during my own research I have come across something that confuses me.
Acceleration= Final velocity - Initial velocity divided by time.
What is confusing me is when your deriving other equations from this you get
at=v - u
Multiply both sides by t gives at=v-u. This confuses me cause I would get something like this
at=vt - ut
So I substituted some values in to see if at=v - u works.
Acceleration= 10 m/sec^2
Time= 2 seconds
Final velocity= 20 m/s
Initial velocity= 10 m/s
???????? 20 does not equal 10 so how does at=v - u work?
Doing it my way I got at= vt - ut
at=vt - ut
Then I thought about cancelling the time term for some reason and I got
a= v - u
Probably being really stupid here and need to go over my rudimentary algebra. Ignore this I got it acceleration is actually 5 I didnt use the equation at the start right
Nov23-13, 12:27 PM
The equations you stated is correct (for the average acceleration, or if the acceleration is constant):
a = (v - u)/t
Multiplying by t you get
at = v - u
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