
#1
Nov2313, 11:35 AM

P: 44

Sorry I can't get latex working so bear with me as I am new to it. I start Alevel physics in a week and during my own research I have come across something that confuses me.
Acceleration= Final velocity  Initial velocity divided by time. What is confusing me is when your deriving other equations from this you get at=v  u Multiply both sides by t gives at=vu. This confuses me cause I would get something like this at=vt  ut So I substituted some values in to see if at=v  u works. Acceleration= 10 m/sec^2 Time= 2 seconds Final velocity= 20 m/s Initial velocity= 10 m/s 10*2= 20 2010=10 ???????? 20 does not equal 10 so how does at=v  u work? Doing it my way I got at= vt  ut 20*2= 40 10*2= 20 4020= 20 at=vt  ut Then I thought about cancelling the time term for some reason and I got 10 2010= 10 a= v  u Probably being really stupid here and need to go over my rudimentary algebra. Ignore this I got it acceleration is actually 5 I didnt use the equation at the start right 



#2
Nov2313, 12:27 PM

Engineering
Sci Advisor
HW Helper
Thanks
P: 6,386

The equations you stated is correct (for the average acceleration, or if the acceleration is constant): a = (v  u)/t Multiplying by t you get at = v  u 


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