Solve Wheatstone Bridge: Homework Statement & Equations

So one should take the derivative of the expression for V0.In summary, the conversation discusses solving for part b-d of a problem involving a Wheatstone bridge. The solution involves finding an expression for V0 and taking the derivative to find the change in V0 as a variable is changed. A helpful resource is provided for further explanation.
  • #1
I'mlost
1
0

Homework Statement


I think I got part A. I'm complete lost with b -d and help would be great

Homework Equations



https://www.physicsforums.com/attachment.php?attachmentid=10986&d=1190644998

The Attempt at a Solution


It think part d is ∆V = [(∆R1 - ∆R2 + ∆R3 –∆R4 ) / 4R ] * Vo But I'm not sure

Homework Equations


The Attempt at a Solution

 
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  • #2
See if this explanation helps - http://en.wikipedia.org/wiki/Wheatstone_bridge

In parts b-d, R4 = R + [itex]\Delta R[/itex], and R1 = R2 = R3.

Find an expression for V0 in terms of R1, R2, R3 and R4, then substitute in the appropriate values.

In part d, one is looking for how much V0 changes as [itex]\Delta R[/itex] changes.
 
  • #3
The Wheatstone Bridge is a circuit used to measure unknown resistance values by comparing them to known resistances. It consists of four resistors arranged in a diamond shape, with the unknown resistor (R4) in one arm and the other three resistors (R1, R2, and R3) in the other arms. The circuit is balanced when the ratio of the resistances in one arm is equal to the ratio in the other arm. This allows us to solve for the unknown resistance using the equation:

R4 = (R2/R1) * R3

To solve for the unknown resistance, you can follow these steps:

1. Set up the Wheatstone Bridge circuit with the unknown resistor (R4) in one arm and the other three resistors (R1, R2, and R3) in the other arms.

2. Vary the variable resistor (R2) until the voltmeter reads zero. This indicates that the circuit is balanced.

3. Measure the resistance values of R1, R2, and R3 using a multimeter.

4. Use the equation R4 = (R2/R1) * R3 to solve for the unknown resistance, R4.

For part b, you will need to use the same equation, but this time, you will vary the variable resistor (R1) until the voltmeter reads zero. This will give you the ratio of R2/R1, which you can then use to solve for R4.

For part d, your equation looks correct. To find the change in voltage (∆V), you will need to take the difference between the initial and final values of R1, R2, R3, and R4, and plug them into the equation. This will give you the change in voltage across the bridge, which can then be used to calculate the unknown resistance, R4.
 

1. What is a Wheatstone Bridge?

A Wheatstone Bridge is an electrical circuit that is used to measure unknown electrical resistance by balancing two legs of a bridge circuit.

2. How does a Wheatstone Bridge work?

A Wheatstone Bridge works by using a known resistance, a variable resistance, and two other resistances in a bridge circuit. As the variable resistance is adjusted, the circuit reaches a point of balance where there is no current flow through the bridge. This balance point can then be used to calculate the unknown resistance.

3. What are the equations used in a Wheatstone Bridge?

The equations used in a Wheatstone Bridge are: R1/R2 = R3/R4 and Rx = (R3/R4) * R2, where Rx is the unknown resistance, R1 and R2 are the known resistances, and R3 and R4 are the variable and unknown resistances.

4. What are some common applications of the Wheatstone Bridge?

The Wheatstone Bridge is commonly used in strain gauge measurements, resistance thermometers, and strain gauge pressure sensors. It is also used in bridge amplifiers for measuring small changes in resistance, such as in temperature sensors.

5. How do I solve a Wheatstone Bridge problem?

To solve a Wheatstone Bridge problem, you will need to know the values of at least three resistances, including the unknown resistance. From there, you can use the equations R1/R2 = R3/R4 and Rx = (R3/R4) * R2 to calculate the unknown resistance. It is important to pay attention to the units of the resistances and make sure they are all in the same unit before solving the equations.

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