What is the RAM of carbon in a sample based on data from a mass spectrum?

FONT]In summary, the conversation discusses the use of data from a mass spectrum to calculate the mass of a neutron, the relative atomic mass (RAM) of 13C, and the RAM of carbon in a sample. The method involves multiplying the mass of each ion by its relative abundance and then finding the weighted average of the results. The final calculations for the RAM of 13C and carbon in the sample are 0.143 and 12.01, respectively.
  • #1
123Sub-Zero
4
0
1.Some data obtained from the mass spectrum of a sample of carbon are given below.
Ion 12C+ 13C+
Absolute mass of one ion/g 1.993 x 10-23 2.158 x 10-23
Relative abundance/ % 98.9 1.1
Use the data to calculate the mass of one neutron, the RAM of 13C and the RAM of carbon in the sample.
You may neglect the mass of an electron.
Work out:
1.Mass of one neutron
2.RAM of 13C
3.RAM of carbon in the sample
I know how to work out the RAM form a mass spectrometer graph but cannot work this out. I presume you multiply the mass of one ion by relative abundance to (for the RAM questions) but then don't know the next step.
 
Physics news on Phys.org
  • #2
[tex]A_{r} of samples:\\
^{13}C:~~\frac{13 x 1.1}{100} = 1.43 x 10^{-1} = 0.143\\
Carbon:~~\frac{(12 x 98.9)~+~(13 x 1.1)}{(98.9 + 1.1)} = 12.011 = 12[/tex]
 
Last edited:
  • #3


In order to calculate the mass of one neutron, we can use the fact that the mass of one ion is equal to the mass of one proton plus the mass of one neutron. Therefore, we can subtract the mass of one proton (1.0073 amu) from the mass of 12C+ (1.993 x 10^-23 g) to get the mass of one neutron, which is approximately 1.986 x 10^-23 g.

To calculate the RAM of 13C, we can use the formula for calculating average atomic mass. This formula takes into account the mass and relative abundance of each isotope present. In this case, we have two isotopes, 12C and 13C, with relative abundances of 98.9% and 1.1%, respectively. Plugging these values into the formula, we get:

RAM = (98.9/100)(12 amu) + (1.1/100)(13 amu)
= 11.868 amu + 0.143 amu
= 12.011 amu

Therefore, the RAM of 13C is approximately 12.011 amu.

To calculate the RAM of carbon in the sample, we can use the same formula but with the relative abundance of 12C as 100%, since it is the only isotope present in carbon. This gives us:

RAM = (100/100)(12 amu)
= 12 amu

Therefore, the RAM of carbon in the sample is approximately 12 amu.
 

What is a mass spectrometer?

A mass spectrometer is a scientific instrument that measures the mass-to-charge ratio of ions. It is used to identify and quantify the chemical composition of a sample by ionizing the molecules and separating them based on their mass-to-charge ratio.

How does a mass spectrometer work?

A mass spectrometer works by first ionizing a sample, either through electron impact or electrospray ionization. The ions are then accelerated through an electric field and separated based on their mass-to-charge ratio using a magnetic field. The separated ions are then detected and analyzed to determine the composition of the sample.

What are the applications of a mass spectrometer?

Mass spectrometers have a wide range of applications in various fields such as chemistry, biology, and forensics. They are used for analyzing the composition of substances, identifying unknown compounds, and studying chemical reactions and processes.

What are the different types of mass spectrometers?

There are several types of mass spectrometers, including time-of-flight, quadrupole, ion trap, and magnetic sector instruments. Each type has its own unique features and advantages, making them suitable for different applications.

What are the advantages of using a mass spectrometer?

A mass spectrometer offers several advantages, including high sensitivity, accuracy, and the ability to analyze a wide range of compounds. It also allows for the detection and identification of very small amounts of substances, making it a valuable tool in many research and analytical settings.

Similar threads

  • Advanced Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
4
Views
2K
  • Introductory Physics Homework Help
Replies
8
Views
4K
  • Introductory Physics Homework Help
Replies
4
Views
4K
  • Introductory Physics Homework Help
Replies
2
Views
4K
  • Introductory Physics Homework Help
Replies
1
Views
2K
  • General Engineering
Replies
5
Views
3K
  • Other Physics Topics
Replies
20
Views
23K
  • Astronomy and Astrophysics
Replies
19
Views
4K
  • Biology and Chemistry Homework Help
Replies
7
Views
10K
Back
Top