- #1
kyles
- 2
- 0
I am doing research and was curioius as to how I would obtain useful numbers for efficiencies from the following information, concerning a CHP aero derivative turbine,
Power KW = 43822
Heat Rate LHV KJ/kWH = 8980
From this, can I say that if I ran the machine for an hour I would use 43,882KWH and receive 109311.54KWH of heat out put [ from, (8980kj/kwh x 43822kwh)*1000/(3.6MJ)) = 109311.54KWH ]
However, when I use the table for running at full load, the electrical efficiency of the machine is 39%. I considered that this may be total efficiency but 39% for a CHP seems way too small, should be closer to 60-70 right?
Which means that I put in 43822KWH/.39 = 112364.1KWH but got out 109311+43882=153193KWH.
As I am sure that this is not an over-unity machine, can anyone show me where I am going wrong?
Power KW = 43822
Heat Rate LHV KJ/kWH = 8980
From this, can I say that if I ran the machine for an hour I would use 43,882KWH and receive 109311.54KWH of heat out put [ from, (8980kj/kwh x 43822kwh)*1000/(3.6MJ)) = 109311.54KWH ]
However, when I use the table for running at full load, the electrical efficiency of the machine is 39%. I considered that this may be total efficiency but 39% for a CHP seems way too small, should be closer to 60-70 right?
Which means that I put in 43822KWH/.39 = 112364.1KWH but got out 109311+43882=153193KWH.
As I am sure that this is not an over-unity machine, can anyone show me where I am going wrong?