- #1
rohit99
- 1
- 0
I am practising for my test. The question is to solve a differential equation
dy/dx + y/x + 1 = 5x
y(0) = 1.
The answer that i have come up with is
(xy+y)= 5x^3/3+5x^2/2+c
by substituting the values x=0 and y=1 into the general equation I get
y(x+1)=5x^3/3 + 5x^2/2 +1
as the particular solution.
Can you tell me how will the particular solution look like and why this particular solution exists?
dy/dx + y/x + 1 = 5x
y(0) = 1.
The answer that i have come up with is
(xy+y)= 5x^3/3+5x^2/2+c
by substituting the values x=0 and y=1 into the general equation I get
y(x+1)=5x^3/3 + 5x^2/2 +1
as the particular solution.
Can you tell me how will the particular solution look like and why this particular solution exists?