Calculate Impedance of Copper Coil w/ Iron Core

In summary: J = I/A. So we can rewrite the equation as:∇ × B = μ0I/ANow, let's consider the magnetic field outside the solenoid. We know that the magnetic field lines are still closed loops, but they will be different from the ones inside the solenoid. Using the second equation again, we can find the magnetic field outside the solenoid by considering the iron core. Since the iron core has a higher magnetic permeability than the air or copper, the magnetic field lines will be stronger in the core. This means that the current density, J, will be different in the core compared to outside the solenoid. We can account for this by adding an additional term to
  • #1
levi
5
0
I have to calculate the impedance (=R+j*w*L) of an infinite copper coil (par meter), with an iron core. Given data are the magnetic permeability, conductivity and radius of the copper wire, inside and outside radius of the coil, radius of the core and permeability and conductivity of the iron.

I don't have to use some formula like pouillet's law or something like that, but start from maxwell's equations or EQS or MQS approximations. The result should be a function of the frequency. Hence the symmetry of the problem I think I should use integral equations in cilindrical coordinates, but i have no idea where to start.
Can anyone help me?
thanks
 
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  • #2

Thank you for your question. I am happy to assist you with calculating the impedance of an infinite copper coil with an iron core.

First, let's review some important equations that will help us solve this problem. Maxwell's equations describe the relationship between electric and magnetic fields, and they are the basis for understanding electromagnetic phenomena. The equations are:

1. Gauss's law for electric fields: ∇ · E = ρ/ε0
2. Gauss's law for magnetic fields: ∇ · B = 0
3. Faraday's law: ∇ × E = -∂B/∂t
4. Ampere's law: ∇ × B = μ0(J + ε0∂E/∂t)

In these equations, ε0 is the permittivity of free space, μ0 is the permeability of free space, ρ is the electric charge density, J is the current density, and ∂/∂t denotes the partial derivative with respect to time.

To solve this problem, we will use the equations for the magnetic field in cylindrical coordinates, which are:

∇ · B = 0
∇ × B = μ0(J + ε0∂E/∂t)

We will also use the equation for the electric field in cylindrical coordinates:

∇ · E = ρ/ε0

Now, let's consider the geometry of the problem. We have an infinite copper coil with an iron core. We can assume that the coil is wound tightly, so we can consider the coil to be a solenoid. The iron core is cylindrical in shape, and it is located inside the coil.

To start, we will consider the magnetic field inside the solenoid. Using the first equation above, we know that the divergence of the magnetic field is zero. This means that the magnetic field lines are closed loops, and there is no net flow of magnetic field through any closed surface. This is true for both the inside and outside of the solenoid.

Next, we will use the second equation to find the magnetic field inside the solenoid. Since the electric field is zero inside the solenoid, we can simplify the equation to:

∇ × B = μ0J

We know that the current density, J, is related to the current, I, and the cross-sectional area of the solenoid, A,
 
  • #3


To calculate the impedance of an infinite copper coil with an iron core, we can start by using Maxwell's equations in cylindrical coordinates. These equations describe the behavior of electromagnetic fields in a given material. In this case, we are interested in the behavior of the electric and magnetic fields within the copper coil and iron core.

First, we can use Ampere's law to calculate the magnetic field within the coil. This law states that the line integral of the magnetic field around a closed loop is equal to the current passing through the loop multiplied by the permeability of the material. In this case, we can use the magnetic permeability of copper to calculate the magnetic field within the coil.

Next, we can use Faraday's law to calculate the induced electric field within the coil. This law states that the line integral of the electric field around a closed loop is equal to the rate of change of the magnetic flux passing through the loop. In this case, we can use the magnetic field calculated from Ampere's law and the radius of the coil to calculate the induced electric field.

Now, we can use Ohm's law to calculate the current within the coil. This law states that the current passing through a material is equal to the electric field divided by the material's conductivity. In this case, we can use the induced electric field and the conductivity of copper to calculate the current within the coil.

Finally, we can use the impedance formula, which is equal to the resistance (R) plus the reactance (j*w*L), to calculate the impedance of the coil. The resistance can be calculated from the current and the radius of the coil, while the reactance can be calculated from the current and the inductance (L) of the coil, which can be found using the magnetic field and the radius of the coil.

To take into account the iron core, we can use the magnetic permeability and conductivity of iron in the calculations for the magnetic field and current. This will affect the overall impedance of the coil and must be taken into consideration in the calculations.

In summary, to calculate the impedance of an infinite copper coil with an iron core, we can use Maxwell's equations, Ampere's law, Faraday's law, Ohm's law, and the impedance formula. With these equations and the given data, we can find a function of frequency that describes the impedance of the coil.
 

What is the purpose of calculating the impedance of a copper coil with an iron core?

The impedance of a coil with an iron core is an important factor in determining its electrical characteristics and performance. It can help in designing and optimizing the coil for specific applications, such as inductors for electronic circuits or electromagnets for industrial use.

How is the impedance of a copper coil with an iron core calculated?

The impedance of a copper coil with an iron core is calculated using the formula Z = √(R^2 + (ωL)^2), where R is the resistance of the coil, ω is the angular frequency, and L is the inductance of the coil. The values for R and L can be measured or calculated based on the dimensions and materials of the coil.

What factors affect the impedance of a copper coil with an iron core?

The main factors that affect the impedance of a copper coil with an iron core are the dimensions and materials of the coil. The number of turns in the coil, the diameter of the wire, and the permeability of the iron core all play a role in determining the coil's impedance.

Why is the iron core used in a copper coil?

The iron core is used in a copper coil to increase the inductance and thus the impedance of the coil. This is because the iron core has a higher permeability than air, which allows for more magnetic flux to be generated and captured within the coil.

What are some practical applications of calculating the impedance of a copper coil with an iron core?

The impedance of a copper coil with an iron core is important in various applications such as power supplies, motors, transformers, and antennas. It is also used in wireless power transfer systems, audio equipment, and other electronic devices that require inductors.

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