How Is Lift Force Calculated for a Helicopter?

[tennisacerg]

A 4600 kg helicopter accelerates upward at 2.0 m/s^2. What lift force is exerted by the air on the propellors?

I don't know how to do it.

Please help

 

[geoffjb]

A 4600 kg helicopter accelerates upward at 2.0 m/s^2. What lift force is exerted by the air on the propellors?

I don't know how to do it.

Please help

Draw a Free Body Diagram (with every force) and remember that $F=ma$ and $w=mg$.

 

[kyle8921]

I can assist you with this problem. The lift force exerted by the air on the propellers can be calculated using the equation F = ma, where F is the force, m is the mass of the helicopter, and a is the acceleration. In this case, the mass of the helicopter is given as 4600 kg and the acceleration is 2.0 m/s^2. Therefore, the lift force exerted by the air on the propellers is:

F = (4600 kg)(2.0 m/s^2) = 9200 N

This means that the air is exerting a force of 9200 N on the propellers to accelerate the helicopter upward at 2.0 m/s^2. It is important to note that this is the net force exerted by the air on the propellers, as it takes into account both the lift force and any other opposing forces, such as drag. I hope this helps clarify the problem for you.