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iluvcats
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HELP on Hardy Weinberg Problem!
the allel for unattached earlobes is dominant over the allele for attached earlboes. in a population of 500 individuals 25% show the recessive pheontype. how many individuals woul you expect to be homozygous dominant and heterozygous for this trait?
p^2+q^2=1.0
p^2+2pq+q^2=1.0
q^2=.25
p^2+.25=1.0
p^2=.75
.75 x 500
p^2 =375 people are homozygous dominant
square root of .75 = .87
square root of .25 =.5
2(.87)(.5)
.87
.87 X 500 =435 people are heterozygous
this on one of my many attempts with this problem. i REALLY need some help with it. someone to walk me step by step through it. i know the equation, i have spent plenty of time working on it and i have more of the same problems so if i don't understand one of them than i can't do any. i have looked through all my textbooks and am unable to understand it. so if you could please help me out and help me step by step with so i can understand how to apply the formula to the problem i would really appreciate it. thank you
Homework Statement
the allel for unattached earlobes is dominant over the allele for attached earlboes. in a population of 500 individuals 25% show the recessive pheontype. how many individuals woul you expect to be homozygous dominant and heterozygous for this trait?
Homework Equations
p^2+q^2=1.0
p^2+2pq+q^2=1.0
The Attempt at a Solution
q^2=.25
p^2+.25=1.0
p^2=.75
.75 x 500
p^2 =375 people are homozygous dominant
square root of .75 = .87
square root of .25 =.5
2(.87)(.5)
.87
.87 X 500 =435 people are heterozygous
this on one of my many attempts with this problem. i REALLY need some help with it. someone to walk me step by step through it. i know the equation, i have spent plenty of time working on it and i have more of the same problems so if i don't understand one of them than i can't do any. i have looked through all my textbooks and am unable to understand it. so if you could please help me out and help me step by step with so i can understand how to apply the formula to the problem i would really appreciate it. thank you