Three species reversible reaction rate

In summary, a three species reversible reaction rate refers to a chemical reaction involving three different species that can react with each other and revert back to the original reactants. The rate is determined by the forward and backward reactions and can be affected by factors such as temperature, concentration, pressure, and catalysts. The equilibrium constant represents the ratio of the forward and backward rate constants and can be used to manipulate the rate of the reaction by changing conditions or using a catalyst.
  • #1
babbagee
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The problem statement says to derive the concentration as a function of time for the general three species first order reactions. I have attached an image of the problem, so see the image for the reaction.



I have written the reaction rates for all the reactions but I am having trouble after that.

The reaction rates that I have are,

[itex]\frac{dCA}{dt}[/itex]=-k[itex]_{2}[/itex]C[itex]_{A}[/itex]+k[itex]_{2}[/itex]C[itex]_{Q}[/itex]-k[itex]_{3}[/itex]C[itex]_{A}[/itex]+k[itex]_{4}[/itex]C[itex]_{S}[/itex]

[itex]\frac{dCQ}{dt}[/itex]=k[itex]_{1}[/itex]C[itex]_{A}[/itex]-k[itex]_{2}[/itex]C[itex]_{Q}[/itex]-k[itex]_{5}[/itex]C[itex]_{Q}[/itex]+k[itex]_{6}[/itex]C[itex]_{S}[/itex]

[itex]\frac{dCS}{dt}[/itex]=k[itex]_{3}[/itex]C[itex]_{A}[/itex]-k[itex]_{4}[/itex]C[itex]_{S}[/itex]+k[itex]_{5}[/itex]C[itex]_{Q}[/itex]-k[itex]_{6}[/itex]C[itex]_{S}[/itex]

Where k1 and k2 are the forward and reverse rate coefficient for A[itex]\rightleftharpoons[/itex]Q reaction

k4 and k3 are the forward and reverse rate coefficient for A[itex]\rightleftharpoons[/itex]S reaction

and
k5 and k6 are the forward and reverse rate coefficient for Q[itex]\rightleftharpoons[/itex]S reaction

from stoichiometry, I also know that C[itex]_{A}[/itex]+C[itex]_{Q}[/itex]+C[itex]_{S}[/itex]=C[itex]_{A0}[/itex]+C[itex]_{Q0}[/itex]+C[itex]_{S0}[/itex]=C[itex]_{T0}[/itex] where C[itex]_{T0}[/itex] is the total mols

Initial Conditions:
C[itex]_{A}[/itex](t=0)=C[itex]_{A0}[/itex]
C[itex]_{Q}[/itex](t=0)=C[itex]_{Q0}[/itex]
C[itex]_{S}[/itex](t=0)=C[itex]_{S0}[/itex]

So I have three differential equations which I am having a hard time solving, If anyone could help it would be greatly appreciated.

Thanks In advance.
 

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  • #2
The solution to this problem would be to use the method of separation of variables. First, rearrange each differential equation to the form: \frac{dC_{A}}{C_{A}} = -k_{2}dt + k_{2}dt - k_{3}dt + k_{4}dt\frac{dC_{Q}}{C_{Q}} = k_{1}dt - k_{2}dt - k_{5}dt + k_{6}dt\frac{dC_{S}}{C_{S}} = k_{3}dt - k_{4}dt + k_{5}dt - k_{6}dtThen, integrate both sides to get: ln(C_{A}) = -k_{2}t + k_{2}t - k_{3}t + k_{4}t + C_{A0}ln(C_{Q}) = k_{1}t - k_{2}t - k_{5}t + k_{6}t + C_{Q0}ln(C_{S}) = k_{3}t - k_{4}t + k_{5}t - k_{6}t + C_{S0}Finally, take the exponential of both sides to get: C_{A} = C_{A0}e^{-k_{2}t + k_{2}t - k_{3}t + k_{4}t} C_{Q} = C_{Q0}e^{k_{1}t - k_{2}t - k_{5}t + k_{6}t} C_{S} = C_{S0}e^{k_{3}t - k_{4}t + k_{5}t - k_{6}t} This is the concentration as a function of time for the general three species first order reactions.
 

1. What is a three species reversible reaction rate?

A three species reversible reaction rate refers to a chemical reaction involving three different species (molecules or atoms) that can react with each other to form products, but can also revert back to the original reactants. This type of reaction is also known as a reversible reaction, meaning it can proceed in both forward and backward directions.

2. How is the rate of a three species reversible reaction determined?

The rate of a three species reversible reaction is determined by the rate of the forward reaction and the rate of the backward reaction. This is because the reaction is constantly shifting between the formation of products and the reversion back to reactants. The rate of the reaction is typically measured by the change in concentration of the reactants or products over time.

3. What factors can affect the rate of a three species reversible reaction?

The rate of a three species reversible reaction can be affected by a variety of factors, including temperature, concentration of reactants and products, pressure, and the presence of catalysts. These factors can alter the rate of the forward and backward reactions, thus influencing the overall rate of the reaction.

4. What is the significance of the equilibrium constant in a three species reversible reaction?

The equilibrium constant (K) in a three species reversible reaction represents the ratio of the forward and backward rate constants. It is a measure of how much of the products are formed compared to the reactants at equilibrium. A higher equilibrium constant indicates a greater amount of products formed, while a lower equilibrium constant indicates a greater amount of reactants present at equilibrium.

5. How can the rate of a three species reversible reaction be manipulated?

The rate of a three species reversible reaction can be manipulated by changing the conditions of the reaction. For example, increasing the temperature or concentration of reactants can speed up the rate of the reaction, while decreasing these factors can slow it down. Additionally, the use of a catalyst can also increase the rate of the reaction by lowering the activation energy required for the reaction to occur.

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