rocapp said:
The unit for force is not Coulombs .rocapp said:
Doubling distance reduces force to 1/4 , so to compensate for that, charge must be 4 times what is would be at Q . (Of course with opposite sign.)rocapp said:
Coulomb's Law is a fundamental principle in physics that describes the electrostatic interaction between two electrically charged particles. It states that the force between two point charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them. In other words, the closer two charges are and the larger their magnitudes, the stronger the force between them will be.
To calculate the force between two charges, we can use the formula F = k(q1q2)/r^2, where F is the force, k is the constant of proportionality (9 x 10^9 Nm^2/C^2), q1 and q2 are the magnitudes of the two charges, and r is the distance between them. This formula applies for both like and unlike charges.
The SI unit for electric charge is the Coulomb (C). One Coulomb is defined as the amount of charge that passes through a conductor in one second when the current is one ampere.
Coulomb's Law states that the force between two charges is directly proportional to their magnitudes. This means that if two charges of equal magnitude are placed at opposite ends of a system, their forces will cancel out and the system will be in static equilibrium. This concept is important in understanding the stability of atoms and molecules, as well as larger structures in the physical world.
If two charges of equal magnitude are placed at opposite ends of a system, the third charge that will make the system in static equilibrium will have the same magnitude as the other two, but with an opposite sign. This means that if the two existing charges are positive, the third charge should be negative, and vice versa. The distance between the charges will also play a role in determining the exact magnitude of the third charge.
