Pressure at the bottom of a container

[Spirochete]

Homework Statement

In an open glass container, 0.10 m of oil (rho=850 kg/m^3) floats on top of 0.20 m of water (1000 kg/m^3). What is the pressure at the bottom of the glass?

Homework Equations

(rho)(h)(g)= pressure at a depth of h

The Attempt at a Solution

The only thing I'm not sure of is: for the oil, should I consider h to be o.1 m, or the sum of both heights, making h 0.3?

edit: I also know i have to add in 1 atmosphere at the end

 

[Doc Al]

The only thing I'm not sure of is: for the oil, should I consider h to be o.1 m, or the sum of both heights, making h 0.3?

Each fluid gets its own "height". You'll find the sum of both pressures, not heights.

 

[Moetasim]

I would suggest that the height, h, to be considered for the oil should be 0.1 m, as that is the depth at which the oil is located. The total height of the liquid in the container is not relevant for calculating the pressure at the bottom.

Using the equation (rho)(h)(g) = pressure at a depth of h, we can calculate the pressure at the bottom of the container for both the oil and water separately.

For the oil:
Pressure at bottom = (850 kg/m^3)(0.1 m)(9.8 m/s^2) = 833 Pa

For the water:
Pressure at bottom = (1000 kg/m^3)(0.2 m)(9.8 m/s^2) = 1960 Pa

To find the total pressure at the bottom of the container, we can add these two pressures together and also add in 1 atmosphere (101,325 Pa) as mentioned in the problem.

Total pressure at bottom = 833 Pa + 1960 Pa + 101,325 Pa = 104,118 Pa

Therefore, the pressure at the bottom of the glass container is approximately 104,118 Pa.