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Algebra equivalence help 
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#1
Feb1014, 12:56 PM

P: 20

Hi guys,
please could someone tell me how this is equivalent and/or what the algebraic rule is? how is this: a/as + 1 is equivalent to this: 1/s+1/a Thanks a lot for your time and help 


#3
Feb1014, 02:13 PM

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P: 21,311

Assuming that's not what you meant, it could be either ##\frac{a}{as} + 1## or ##\frac{a}{as + 1}## Starting with 1/s + 1/a, the rule for adding fractions says that we need a common denominator, so 1/s + 1/a = a/(as) + s/(as) = (a + s)/(as). This doesn't match any interpretations of what you wrote, so I don't see that what you started with is equal to 1/a + 1/s. 


#4
Feb1014, 05:02 PM

P: 20

Algebra equivalence help
Thanks for the replies. Sorry for the ambiguity i should have used parentheses.
Mark44  What i meant: how is a/(as+1) equivalent to 1/(s+(1/a)) Me_student  i understand a/as=1/s but i dont understand how the other terms equal? i.e. how does the +1 term from a/(as+1) become 1/a? many thanks 


#5
Feb1014, 05:20 PM

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P: 21,311

Can you finish it and show that the last expression is equal to 1/(s + 1/a)? What I did was factor a from both terms in the denominator. 


#6
Feb1114, 01:31 AM

P: 20

Thanks a lot Mark44 you've made that perfectly clear to me, i can see how the expressions equal now. Much appreciated :)



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