How does the Orbital Electron Rotate Permanently without Energy Supply?

In summary, the conversation discusses two long-standing questions about the behavior of orbital electrons. The first question is how an electron can rotate permanently without an energy supply, which is answered by quantum theory through the concept of quantized energy levels. The second question is how an electron can maintain its position without merging into the nucleus under external pressure, which is explained by the equilibrium between the force from the nucleus and the applied force. The conversation also addresses common misconceptions about the Bohr model and suggests further reading for a better understanding of quantum physics.
  • #1
kevinajay
1
0
Is there anyone who knows the answers of these two long-standing questions?

1. How can the orbital electron rotate permanently without energy supply?

2. How can the orbital electron keeps its position without merging into its nucleus when an external pressure applied on it if its kinetic energy balances delicately with its potential energy?

I found a very innovative theory about the questions:
[Crackpot links deleted]

How do you think?
 
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  • #2
Your first question is answered by quantum theory. The "orbits" of the electron in Hydrogen are quantized. The only way an electron can change its energy is by jumping between levels and emitting light. Once the electron sits in the ground state of atom, the lowest energy state, it can't go down anymore because of quantum effects. For more complicated atoms, all the discrete states up to a certain energy are filled, and the atom is stable because of the Pauli exclusion principle which tells you that no two electrons can be in the same quantum state.

To answer your second question, remember that as you compress the atom you are applying an additional force, but the force from the nucleus also gets stronger as the electron moves further in. The system will find a new equilibrium and the electron will not collapse into the nucleus in general. In practice, you could alter the orbit with electric and magnetic fields, but the electron isn't going to crash into the nucleus.

We have known the answers to these questions for many years. There is no confusion even though Dr. Yoon seems to suggest that there is. The confusion lies with him, not with modern atomic theory which is very well founded and well verified experimentally. Dr. Yoon is what we call a crackpot.
 
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  • #3
kevinajay said:
Is there anyone who knows the answers of these two long-standing questions?
1. How can the orbital electron rotate permanently without energy supply?
While this is hardly an answer to the question, recall the revolution that Newton brought to understanding of motion at constant velocity over that achieved by Galileo.

2. How can the orbital electron keeps its position without merging into its nucleus when an external pressure applied on it if its kinetic energy balances delicately with its potential energy?
There are several levels at which one can answer this. One of these has been given to you by PM above. For another picture altogether (a different regime), consider the formation of degenerate neutron matter, as is found in a neutron star.
 
  • #4
kevinajay said:
1. How can the orbital electron rotate permanently without energy supply?
Extra Energy (as from a supply) would only be needed if the orbital electron radiated.
so - why doesn't it radiate?
Its charge density function doesn't change with time - it is spread out over the "orbit". radiation/(absorption) occurs only as the charge density changes.
Sorry, very few 3rd semester intro courses introduce the Bohr model well.

"orbital electron" is probably not a very good phrase, but it is still in use.
Remember - pressure and balancing are FORCE ideas, not ENERGY ideas.
Real balancing occurs near a STABLE equilibrium - it is not "delicate" in the sense of being unstable; it is seldom even very sensitive.
 
  • #5
Electron Orbit

Why is it stated that the orbit of an electron can not change??
Is this incorrect or only relevant to force aplied??
I am confused on this. It would seem that if you applied additional
"excitment" to the electron, say in Hydrogen, that it would change in some manner.
Could such "excitement" be used to bring in the orbit of the electron??
Or would there be an equall force applied keeping it in a stable orbit??
 
  • #6
Ok, this is classic one. people, please STOP talking about an electron's orbit. Using such a language implies that we know the way an electron travels. This is NOT the case.

Secondly, you are referring to the Bohr-model of circular orbits in momentum space, not spatial space. the coordinates are not x,y,z here by the elementary quanta of the L-operator [1]. The only "spatial" notion you can use within this context is the fact that the electron-waves must form closed standing waves along one of the circles.

Thirdly, when talking about an eletcron's position we can only talk in terms of orbitals and corresponding probabilities of finding an electron in such an orbital.

If you guys realize these common misconceptions, most of your questions will solve themselves. It is very important that you all interprete QM and its fundamental concepts in the correct manner.


Err, you guys do know that the Bohr model is hopelessly incomplete, right ?

regards
marlon

[1] Check out this Look for the QM physics section and then the Bohr model.
 
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  • #7
kevinajay said:
1. How can the orbital electron rotate permanently without energy supply?
2. How can the orbital electron keeps its position without merging into its nucleus when an external pressure applied on it if its kinetic energy balances delicately with its potential energy?
You'd better to read "Quantum Physics: Illusion or Reality?" by Alastair Rae, and "Natural Science Founded on A New Atomic Model" by Hansik Yoon in oder to get some answers to your question.
 
  • #8
lightgrav said:
Sorry, very few 3rd semester intro courses introduce the Bohr model well.

In my opinion, introductory courses should not discuss the details of "Bohr orbits" at all, because that implants or reinforces the erroneous concept of electrons moving in deterministic classical trajectories around the nucleus. A detailed analysis of Bohr orbits should be left to a later study of the historical development of QM, after the student is well acquainted with QM as we know it today.

When I teach that material in our second-year "intro modern physics" course, I say that Bohr's important contribution (from a modern perspective) was the concept of discrete atomic energy levels. I use the Balmer/Rydberg formula for the wavelengths of the hydrogen spectrum to get the energy levels for hydrogen in terms of the empirical Rydberg constant. I describe Bohr's circular orbit picture (and the later elliptical-orblt version) quickly and qualitatively, with about the same amount of detail that I give to Thomson's "plum pudding" model. I emphasize that the correct derivation of the energy levels in terms of fundamental constants wasn't found until "real" quantum mechanics came on the scene several years later. I don't do things like find the velocity of the electron in Bohr's circular orbits, or assign any homework invoving such things.
 
  • #9
marlon said:
Err, you guys do know that the Bohr model is hopelessly incomplete, right ?
.
Hopelessly?
If we can’t visualise electrons in orbits how are we explaining the ionisation potentials of i.e. the electrons nearest to the nucleus?
These potentials can be worked out from Wi=1/2me*(Z*Vo)^2 . Vo=constant=~2.1877E6.
Especially when I take in account a heavier relativistic mass of the electron I get good results. How to apply relativity but not imagine a speeding mass?
The Bohr model gives me at least some idea.
 
  • #10
erickalle said:
Hopelessly?
If we can’t visualise electrons in orbits how are we explaining the ionisation potentials of i.e. the electrons nearest to the nucleus?

First of all, how does the fact that we cannot "visualise electrons in orbits" contradict with the fact that we can study the energetics of an atom with tremendous accuracy ?

It is true that Bohr's model was the first big step towards the current QM picture because of the L-quantization but you do need to acknowledge its manifest flaws. That was my point.

But to some extent, hopelessly is perhaps a bit of an overstatement and i do agree with your point on the ionization potential.

How to apply relativity but not imagine a speeding mass?
The Bohr model gives me at least some idea.

I am sorry but i do not really understand what you mean by this. Could you clarify, please.

regards
marlon
 
  • #11
Physicsmonkey said:
Your first question is answered by quantum theory. The "orbits" of the electron in Hydrogen are quantized. The only way an electron can change its energy is by jumping between levels and emitting light. Once the electron sits in the ground state of atom, the lowest energy state, it can't go down anymore because of quantum effects. For more complicated atoms, all the discrete states up to a certain energy are filled, and the atom is stable because of the Pauli exclusion principle which tells you that no two electrons can be in the same quantum state.
Bohr’s theory ( or the old quantum theory as it is now called ) suffered from internal contradictions : in order to determine the radius of the orbit , it was necessary to make use of relations of different kinds- the classical relation
[tex] m\frac {e^2}{r^2_n}[/tex] and the quantum relation
[tex]mv_nr_n=n\hbar[/tex] . The Heisenberg Uncertainty relation
[tex] \Delta\p_x\Delta\x \geq \hbar[/tex] illustrates why the electron does not spiral into the nucleus. If the electron is localized at a definite point x , then its momentum will have an arbitrarily large uncertainty. If on the contrary the electron is in a state with a definite value of [tex]{p_x}[/tex] then it cannot be localized exactly. This also illustrates the fact that the electron is not one of the constituents of the nucleus. What strikes me however is that no-one has yet referred to the virtual transitions of electrons from orbit to orbit through the process of self interaction (i.e the absorption and emission ) of virtual photons. This is the result of another Heisenberg Uncertainty relation which can be stated as
[tex] \Delta{E}\Delta{t}\geq\hbar[/tex]. Thus an electron can move from [tex]E_1\longrightarrow{E_2}\longrightarrow{E_1}[/tex] if it satisfies the relation :
[tex]\frac{\hbar}{\Delta_t}\geq ({E_2}{-} {E_1})[/tex]. This theory of virtual transitions through the absorption and emission of virtual photons is a continuous process.The statement that the electron occupies level [tex]E_1[/tex] should be understood specifically as incessant transitions from the original state to others with an inevitable return every time to the starting level. Virtual transitions don’t require an expenditure of energy. It is only when the electron absorbs a real photon that an actual transition is considered to have been made.
 
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  • #12
McQueen said:
Bohr’s theory ( or the old quantum theory as it is now called ) suffered from internal contradictions : in order to determine the radius of the orbit , it was necessary to make use of relations of different kinds- the classical relation
[tex] m\frac {e^2}{r^2_n}[/tex] and the quantum relation
[tex]mv_nr_n=n\hbar[/tex] . The Heisenberg Uncertainty relation
[tex] \Delta\p_x\Delta\x \geq \hbar[/tex] illustrates why the electron does not spiral into the nucleus. If the electron is localized at a definite point x , then its momentum will have an arbitrarily large uncertainty. If on the contrary the electron is in a state with a definite value of [tex]{p_x}[/tex] then it cannot be localized exactly. This also illustrates the fact that the electron is not one of the constituents of the nucleus. What strikes me however is that no-one has yet referred to the virtual transitions of electrons from orbit to orbit through the process of self interaction (i.e the absorption and emission ) of virtual photons. This is the result of another Heisenberg Uncertainty relation which can be stated as
[tex] \Delta{E}\Delta{t}\geq\hbar[/tex]. Thus an electron can move from [tex]E_1\longrightarrow{E_2}\longrightarrow{E_1}[/tex] if it satisfies the relation :
[tex]\frac{\hbar}{\Delta}{t}\geq ({E_2}{-} {E_1})[/tex]. This theory of virtual transitions through the absorption and emission of virtual photons is a continuous process.The statement that the electron occupies level [tex]E_1[/tex] should be understood specifically as incessant transitions from the original state to others with an inevitable return every time to the starting level. Virtual transitions don’t require an expenditure of energy. It is only when the electron absorbs a real photon that an actual transition is considered to have been made.

I'm not sure why you are addressing PM's comment using the outdated Bohr's model. Why aren't you using the standard QM approach that we teach to every physics undergraduate students? Is there something wrong with that?

Secondly, I don't need to cause a "real" transition only when "electron absorbs a real photon". I can bombard an atom with electrons and cause such an excitation. Your fluorescent light bulb works this way. What this means is that how you excite an atom is irrelevant. If you can sneeze at it to cause a transition, then that works too. I also don't think you should be using "virtual transition" as an explanation for this, especially since you are still using the Bohr model. Keep in mind the rules against over speculative posting.

Zz.
 
  • #13
ZapperZ said:
I'm not sure why you are addressing PM's comment using the outdated Bohr's model. Why aren't you using the standard QM approach that we teach to every physics undergraduate students? Is there something wrong with that?
You are missing the WHOLE point . What about virtual transitions ?
 
  • #14
McQueen said:
You are missing the WHOLE point . What about virtual transitions ?

And you're missing a physics lesson. What about The Schrodinger Equation?

Or are you hijacking this thread to another topic other than the OP?

Zz.
 
  • #15
McQueen said:
What strikes me however is that no-one has yet referred to the virtual transitions of electrons from orbit to orbit through the process of self interaction (i.e the absorption and emission ) of virtual photons.

Whose theory is this? I don't remember seeing it in any textbook. Can you provide a reference to a textbook or research paper that describes it?
 
  • #16
marlon said:
I am sorry but i do not really understand what you mean by this. Could you clarify, please.
regards
marlon
The fact that when I include relativistic mass in my calculations the potentials are even closer to given value’s, reinforces my idea of a speeding particle round a nucleus. In the past I’ve been thought that we just have to accept particle and wave duality.
Another (cheeky) point. What does the Latin under your name translate to?
Thanks.
eric
 
  • #17
erickalle said:
The fact that when I include relativistic mass in my calculations the potentials are even closer to given value’s, reinforces my idea of a speeding particle round a nucleus. In the past I’ve been thought that we just have to accept particle and wave duality.
I thought that the electron in the atom did not move at relativistic speeds , could you clarify , please.
 
  • #18
ZapperZ said:
And you're missing a physics lesson. What about The Schrodinger Equation? Or are you hijacking this thread to another topic other than the OP?

Ok. Let me attempt an explanation. The original question by Kevinajay was
1. How can the orbital electron rotate permanently without energy supply?
And
2. How can the orbital electron keeps its position without merging into its nucleus when an external pressure applied on it if its kinetic energy balances delicately with its potential energy?

Where does Schrodinger’s equation come into all this ? Schrodinger’s equation can be used to consider the motion of a microparticle in a limited region of space or , in other words in a potential well . ( For example the motion of an electron in an atom} Such a motion is called finite and the electron is in a bound state. In this case the time-independent Schrodinger equation is used. :

[tex]-\frac{\hbar^2}{2m}\frac{d^2}{dx^2}\varphi_E\(x)+[U(x){-}E]\varphi_E\(x)=0 [/tex]

By solving the Schrodinger equation under certain boundary conditions imposed on the wave function and its first derivative , the spectrum of the values of the energy of the electrons and the wave functions of the stationary states can be found. So this is about eigen values. The question was how does the electron rotate permanently without energy supply. To which I had replied that this was achieved through constant “virtual” transitions using Hesienbergs Uncertainty relation , is there anything wrong with that ?. The original problem with transitions was that of quantum jumps. It had to do with the contradictions observed while considering the jump of an electron one orbit (energy level if you like ) to another . Whatever the speed of transition from one orbit ( energy level ) to another it had to last for some finite time. What is the energy of the electron in the intermediate time. Owing to which Schrodinger had made the famous remark those damned quantum jumps…. The contradiction regarding quantum transitions is overcome by making use of the idea of duality or more precisely the uncertainty relation and the super position of states. Take the two energy levels [tex] {E_1}[/tex] and [tex]{E_2}[/tex] this can be denoted as <1| and <2| respectively it is also possible to get the state : <f|= <f|1|> + <f|2><2| Mesurement of the energy of the electron in this state leads either to the result [tex]{E_1}[/tex] or to the result [tex]{E_2}[/tex] . According to this the microparticle can simultaneously occupy [tex] {E_1}[/tex] and [tex]{E_2}[/tex].
Such a state can only be explained through “virtual’ transitions.
 
  • #19
The particle doesn't "spiral into the nucleus" because there is a lowest energy state amongst the solutions of the Schrodinger equation. The notion that the particle has some path is itself flawed, and I don't understand why you acted as if I was making use of the Bohr model in my answer. I wasn't. Now, you can couple your atom to a classical radiation field or even go all the way and couple it to the full quantum radiation field. Either way, the atom is stable because there is a lowest energy state. If there was no lowest energy state then the atom wouldn't be stable regardless of any virtual transitions you might want to talk about. Adding all the complexity of the quantized radiation field gains you nothing in terms of explaining the basic stability of the atom (it does do a lot of other neat things for you, of course). Furthermore, as I said in my first post the electron moves between levels when it emits or absorbs light, be it real or virtual photons.
 
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  • #20
You sound as if you have never done Lagrangian/Hamiltonian mechanics, nor calculus of variation, where "stationary" solution is derived.

Secondly, what in the world is "U(x) - E"?

Thirdly, have you EVER worked though to the solution of one of these? Or did you just read about it somewhere on the 'net?

Fourth, please show citation for your "virtual" stuff, as was asked before. This will be the LAST time such a request will be made before this is deleted. Any further "theory" on this can only be sent to the IR section.

Zz.
 
  • #21
physicsmonkey said:
The particle doesn't "spiral into the nucleus" because there is a lowest energy state amongst the solutions of the Schrodinger equation. The notion that the particle has some path is itself flawed, and I don't understand why you acted as if I was making use of the Bohr model in my answer.
It was not my intention to imply that you wre making use of the Bohr model of the atom in your answer , in fact I had stated that the Bohr model of the atom is often referred to as the old quantum mechanics.
 
  • #22
ZapperZ said:
Secondly, what in the world is "U(x) - E"?
[tex]{U(x)}[/tex] stands for the potential of an external field.

ZapperZ said:
Fourth, please show citation for your "virtual" stuff, as was asked before. This will be the LAST time such a request will be made before this is deleted. Any further "theory" on this can only be sent to the IR section
I am working on it.
 
  • #23
McQueen said:
[tex]{U(x)}[/tex] stands for the potential of an external field.


REALLY! And what is U(x) - E, which was my full question?

I am working on it.

Work faster, because unless you can cite published papers or texts that show this, this will be deleted. You HAVE already been told about the IR forum.

Zz.
 
  • #24
i just got myself confused.
"1. How can the orbital electron rotate permanently without energy supply?"
did i understand the question? does it say why doesn't it run out of its fuel (energy)?

why would it need some energy to continue? i thought that an object moving through space will continue moving forever; (Newtons law of inertia?); if not disturbed.so where does the question (why doesn't it run out of its fuel) come from?

what am i missing?
 
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  • #25
___ said:
i just got myself confused.
"1. How can the orbital electron rotate permanently without energy supply?"
did i understand the question? does it say why doesn't it run out of its fuel (energy)?
why would it need some energy to continue? i thought that an object moving through space will continue moving forever; (Newtons law of inertia?); if not disturbed.so where does the question (why doesn't it run out of its fuel) come from?
what am i missing?

You're missing the fact that the electron needs to be moving in a closed orbit around the nucleus. This means the charge particle is accelerating. Maxwell equations show that an accelerating charge particle radiates, thus continues to lose energy, causing it to spiral into the attractive potential. This doesn't occur in an atom.

Zz.
 
  • #26
If the electron actually revolved around the nucleus it'd be in accelerating motion and radiate it's energy eventually (pretty damn fast actually) falling to the nucleus.

edit. I'm too slow!
 
  • #27
erickalle said:
The fact that when I include relativistic mass in my calculations the potentials are even closer to given value’s, reinforces my idea of a speeding particle round a nucleus.
Maybe (i have not checked it) but anyhow, you are applying this in a model that states that electrons move in circular orbits arond the nucleus. Circular motion (even with constant velocity) require centripetal acceleration. Since you need to hold on to energy conservation, the electron would spiral down towards to nucleus (loss of energy because an accelerated charged particle radiates as predicted by Maxwell equations). Thus, stable atoms would not exist. This is a very obvious flaw of Bohr's model.

Besides, one cannot make any reasonable assumptions onto the electron's velocity since that would imply you know how the electron's orbit evolves in time (definition of velocity), but then you are forgetting about the HUP, no ?

In the past I’ve been thought that we just have to accept particle and wave duality.
You do.
Another (cheeky) point. What does the Latin under your name translate to?
Thanks.
eric
:rofl: ok, check out the libretto of the Latin Requiem Mass. Just google for it.

marlon
 
  • #28
McQueen said:
I thought that the electron in the atom did not move at relativistic speeds , could you clarify , please.
IF I look at the Bohr model then the speed of the electron increases with atomic number Z. So V=Z*Vo. As Vo is ~2E6 you can see that we soon get into relativistic speeds. (I am looking at the first electron in the K-shell).
OK folks, I have a confession to make.
The calculated values using the formula of reply # 9 are actually pretty close to ionisation values given in the handbook of chemistry and physics (the values for Z=1 to 29 are given). However these calculated values are consistently lower then given values, that’s why I got the idea in the past that a higher relativistic mass including formula: m=mo(1-(ZVo/C)^2)^-0.5 would give a better result.
I’ve done the calculations again and these new values are of course indeed higher but they are now too high by a slightly bigger margin.
 
  • #29
But, but, but... in high school Chemistry, they taught us that electrons orbit around the nucleus; that there are a few specific distances at which these orbits form; that the farther out from the nucleus, the more energy the electrons have; that the farther out from the nucleus, the more electrons can fit in the same orbit level; and etc.

Are you implying that they lied to us in high school?

:wink: :tongue2:
 
  • #30
Well you got lied to a bit. An all out quantum mechanical assault on atoms would be way beyond the scope of high school chemistry courses.
 
  • #31
inha said:
Well you got lied to a bit. An all out quantum mechanical assault on atoms would be way beyond the scope of high school chemistry courses.

yeah! in my early years i was told that water (and every thing) contract on cooling, and now they say:mad: "sometimes water expands on cooling and expands on heating!"
:grumpy:
i know this has got something to do with th molecules' kinetic energy, higher the temp. higher the energy but...:grumpy:
 
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1. How does the orbital electron rotate permanently without energy supply?

The orbital electron rotates permanently due to its intrinsic property known as angular momentum. This momentum is conserved and does not require any external energy supply to maintain its rotation.

2. What is the role of the electron's charge in its perpetual rotation?

The electron's charge plays a significant role in its perpetual rotation. As the electron moves around the nucleus, its charge creates a magnetic field, which interacts with the magnetic field of the nucleus, resulting in a stable orbit.

3. Can the electron's perpetual rotation be explained by classical physics?

No, the electron's perpetual rotation cannot be explained by classical physics. Classical physics cannot account for the quantum nature of the electron, which allows it to exist in multiple energy levels and behave as both a particle and a wave.

4. Does the electron's perpetual rotation violate the law of conservation of energy?

No, the electron's perpetual rotation does not violate the law of conservation of energy. The electron's angular momentum is conserved, and its perpetual rotation does not require any additional energy input.

5. How does the electron's perpetual rotation contribute to the stability of atoms?

The electron's perpetual rotation contributes to the stability of atoms by creating a balance between the attractive force of the nucleus and the repulsive force of the electron's charge. This balance allows atoms to maintain their structure and prevents them from collapsing.

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