Force exerted onto the pipe by a shrunk fit ring

In summary, the conversation is about calculating the force exerted onto a pipe by a stainless steel ring that is heated and shrunk fit onto the pipe. The factors that need to be considered are the inner and outer diameters of the pipe and ring, their starting and final temperatures, and the differential thermal expansion between the two materials. The person asking for help provides the dimensions of the pipe and ring and asks for the force exerted on the pipe.
  • #1
sunshine76
2
0
hi, this is my first post here in this forum. i would like somebody here to help me in calculating the force exerted onto the pipe by a stainless steel ring of 10mm thickness, when it is shrunk fit on to the pipe by heating.

thanks in advance
 
Engineering news on Phys.org
  • #2
What are the inner and outer diameters. Theoretically, it depends on whether thay are considered thick walled cylinders, i.e. ID/t<10.
 
  • #3
As the steel ring cools, it thermally contracts. The steel ring will be in tension and the pipe on to which it shrinks will be in compression.

The key about thermal strain is that it does produces displacement without stress.

One needs the IDs/ODs of the pipe and steel ring, and the starting and final temperatures of the steel ring. One can simply the problem by assuming the pipe does not change temperature from its initial temperature (e.g. room temp) and this is the final temperature of the steel ring.

When two dissimilar metals are mated, one must be concerned with differential thermal expansion - a consequence of different thermal expansion coefficients and/or thermal gradients.
 
  • #4
Pipe OD: 127mm
Pipe ID: 115mm

Ring OD:133mm
Ring ID: 126.5mm
Ring width:20mm

Please anyone tell me when the ring is heated and fitted onto the pipe, what will be the force exerted on the pipe?
 
  • #5
Is this homework?
 

1. How does a shrunk fit ring affect the force exerted onto a pipe?

A shrunk fit ring is a type of fastening method that involves heating the ring to expand it and then placing it onto the pipe. As the ring cools and contracts, it exerts a compressive force onto the pipe, creating a tight and secure fit. This force can help to strengthen the connection between the ring and the pipe, providing additional support and stability.

2. What factors affect the amount of force exerted by a shrunk fit ring?

The amount of force exerted by a shrunk fit ring can be affected by several factors, including the size and dimensions of the ring and pipe, the materials used, the temperature and method of heating, and the amount of interference (or difference in diameters) between the ring and pipe.

3. How is the force exerted by a shrunk fit ring calculated?

The force exerted by a shrunk fit ring can be calculated using the formula F = P x A, where F is the force exerted, P is the pressure applied, and A is the surface area of contact between the ring and pipe. The pressure can be determined based on the ring's material properties and the amount of interference between the ring and pipe.

4. What are the advantages of using a shrunk fit ring for pipe connections?

Shrunk fit rings offer several advantages for pipe connections. They provide a strong and secure connection, with the compressive force helping to prevent the pipe from slipping or moving. They also distribute the stress and load evenly across the connection, reducing the risk of failure or damage. Additionally, they have a higher load-carrying capacity compared to other fastening methods, making them suitable for heavy-duty applications.

5. Are there any limitations or risks associated with using shrunk fit rings for pipe connections?

While shrunk fit rings offer many benefits, there are also some limitations and risks to consider. The installation process can be time-consuming and requires specialized equipment, making it more costly compared to other fastening methods. There is also a risk of damaging the pipe or ring if the heating or cooling process is not done correctly. In some cases, the compressive force exerted by the ring may be too much for the pipe to handle, leading to deformation or failure. It is important to carefully consider these factors and ensure proper installation to avoid any potential issues.

Similar threads

Advice on pressure drop calculation
    • Mechanical Engineering
Replies
2
Views
869
Pipe Design to pump sea water from the ocean to a boiler via intermediate tanks
    • Mechanical Engineering
Replies
4
Views
1K
Underground pump vault airflow considerations
    • Mechanical Engineering
Replies
15
Views
816
Converting Pipe Displacement into forces on a Bend
    • Mechanical Engineering
Replies
3
Views
1K
Water cooler radiator with unusual air flow direction
    • Mechanical Engineering
Replies
3
Views
590
Pipes & loads.... will it topple over?
    • Mechanical Engineering
Replies
10
Views
1K
Bernoulli vs. Reynold Transport Theorem Problem for Raincap
    • Mechanical Engineering
Replies
11
Views
1K
Pressure loss to double wall pipe (ventilation)
    • Mechanical Engineering
Replies
13
Views
2K
Bernoulli equation and parallel pipe branch
    • Mechanical Engineering
Replies
31
Views
2K
Calculate the clamping force to prevent the load from sliding
    • Mechanical Engineering
Replies
4
Views
5K

Hot Threads

Recent Insights

Back
Top