- #1
AnkhUNC
- 91
- 0
[SOLVED] Mass of water in a cloud
One cubic centimeter of a cumulus contains 220 water drops, which have a typical radius of 10 μm. (a) How many cubic meters of water are in a cylindrical cumulus cloud of height 3.0 km and radius 1.0 km? (b) How many 1-liter pop bottles would that water fill? (c) Water has a density of 1000 kg/m^3. How much mass does the water in the cloud have?
OK here is what I have so far I know I'm almost there I'm just making some simple mistake somewhere along the line.
First 1 cm^3 of a cloud = (220 drops/cm^3) which equals 220*10^6 drops/m^3
10 microns = 10*10^-6m = radius of a drop. So the density of a drop = 4.188790205E-5m
Volume of the cloud = (Pi)r^2*h = (Pi)(1000m)^2(3000m) = 942477961m (? messing up here?) But this isn't the answer to (A)?
(B) is just a conversion of (A) so..
(C) Well i guess I only got to (A)
Any help of what I'm doing wrong or how I should be going about this would be appreciated. Thanks,
Homework Statement
One cubic centimeter of a cumulus contains 220 water drops, which have a typical radius of 10 μm. (a) How many cubic meters of water are in a cylindrical cumulus cloud of height 3.0 km and radius 1.0 km? (b) How many 1-liter pop bottles would that water fill? (c) Water has a density of 1000 kg/m^3. How much mass does the water in the cloud have?
Homework Equations
The Attempt at a Solution
OK here is what I have so far I know I'm almost there I'm just making some simple mistake somewhere along the line.
First 1 cm^3 of a cloud = (220 drops/cm^3) which equals 220*10^6 drops/m^3
10 microns = 10*10^-6m = radius of a drop. So the density of a drop = 4.188790205E-5m
Volume of the cloud = (Pi)r^2*h = (Pi)(1000m)^2(3000m) = 942477961m (? messing up here?) But this isn't the answer to (A)?
(B) is just a conversion of (A) so..
(C) Well i guess I only got to (A)
Any help of what I'm doing wrong or how I should be going about this would be appreciated. Thanks,