The Real Purpose of Laplace/Fourier Transform?

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In summary, the Laplace transform converts a differential equation into an algebraic one, making it easier to solve. The Fourier transform allows us to separate a signal into its frequency components, providing us with a mathematical way to understand how systems behave in the frequency domain. These transforms have many uses in various fields such as antenna design, optics, and X-ray diffraction. They do not alter the signal, but rather represent it in a more convenient form for manipulation. The purpose of these transforms is to convert signals into equivalent forms that are easier to work with, and their uses depend on the specific application.
  • #1
Peon666
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Well, I do under stand *what* they do but I have trouble understanding the purpose of these transforms in simple words. Laplace transform converts an arbitrary single into exponentials while Fourier transform converts a given signal into sinusoids.

As for the purpose, is the following right?:

We use these techniques, basically, to convert a signal with *no form* into signals with can be specified with certain equations and into specific portions with form. Is that right?

Thanks.
 
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  • #2
From a purely selfish point of view, taking the transform of a differential equation changes it into an algebraic one.

Which would you prefer to solve?
 
  • #3
The question doesn't have a proper answer. Maths is a set of symbolic operations and it stands on its own. Sometimes the operations have a correspondence to some physical reality and sometimes not. The two transforms you quote happen to be of use in solving problems in the 'real world' so I would say they have 'uses' rather than "purposes".
Btw, the Fourier transform is not only used to transform between frequency and time domains - it can be used in spatial / angular domains too (Antenna design, optics and X ray diffraction). Same sums - different applications.
 
  • #4
I can only tell the uses of Laplace/Fourier transform which I know. There may be plenty too which I don't know. But there can't be an answer if you ask "purpose" of those transforms. It depends on people who use it for the given application.
In general any transform if used will represent the given signal into an equivalent form which is convenient for the user to manipulate.
Well, Laplace transform can be used solve differential equations in a simple manner. The way it is done is once you take the Laplace transform of given differential equation, it will be converted to algebraic equation which can be easily manipulated and taking inverse Laplace transform will give solution to the equation.
Fourier transform represents the signal by its frequency content. If I want to know the frequency spectrum of my signal in hand, FT is the best choice.
Note: Any good transform won't alter the signal. It just converts the signal into its equivalent form in another domain. Nothing lost or nothing gained.
 
  • #5
Have you ever used phasors before? Take the Fourier transform of [tex]i=C \frac{d v}{dt}[/tex], and rewrite this in the form of [tex]Z(\omega)=\frac{V(\omega)}{I(\omega)}[/tex]. What do you get?
 
  • #6
Sorry I pressed submit too soon...

Note: There are many more uses of the fourier/laplace transform and mine was just a very very small example.
 
  • #7
Maybe a real world example would help make it clear. Think of the way that you hear sound. Let's say that someone is pressing two piano keys at the same time. If you have some musical training then you should be able to figure out which keys were pressed but anyone will know that they're hearing one high-pitched key and one low-pitched key. How can you know that? You're ear is only getting one signal, the mixed sound of two keys. Somehow, you're brain is able to separate the notes.

Intuitively, we know that we should be able to take a signal and separate out it's frequency components just like our brain does. The Fourier transform gives us a mathematical way to do it. It takes a time signal and transforms it into a spectrum of frequency components. It allows us to work in the frequency domain to understand how systems will behave.
 

1. What is the Laplace/Fourier Transform?

The Laplace/Fourier Transform is a mathematical tool used to convert a function in the time domain into a function in the frequency domain. It is used in many fields, including physics, engineering, and signal processing.

2. What is the purpose of using the Laplace/Fourier Transform?

The main purpose of using the Laplace/Fourier Transform is to simplify the analysis of complex systems or signals. It allows us to break down a complex function into simpler components in the frequency domain, making it easier to understand and manipulate.

3. How is the Laplace/Fourier Transform different from other mathematical transformations?

The Laplace/Fourier Transform is unique in its ability to convert a function from the time domain to the frequency domain. Other mathematical transformations, such as the Fourier Series, only work for periodic functions.

4. What are some practical applications of the Laplace/Fourier Transform?

The Laplace/Fourier Transform has numerous practical applications, including image and signal processing, control systems, and electronics. It is also used in fields such as quantum mechanics, fluid dynamics, and finance.

5. Can the Laplace/Fourier Transform be used for both continuous and discrete functions?

Yes, the Laplace/Fourier Transform can be applied to both continuous and discrete functions. However, the formulas for each type of function will differ slightly. For continuous functions, the Laplace Transform is used, while for discrete functions, the Fourier Transform is used.

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